You have a 450 nF capacitor and wish to combine it with one other to make a combined capacitance of 1.50 µF . You are given a capacitor C1 (given). You want to add a 2nd capacitor C2 (unknown) to give an equivalent capacitance of Ceq (given). Ceq is greater than C1, therefore C2 must be added to C1. The only way this happens if the capacitors are hooked in parallel where: Ceq = C1+ C2 Solving for C2: C2 = Ceq - C1 Write your answer in uF.

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Per attached screen shots, I was given later, second screen shot as hint.

Can explain the rudimentary idea of capacitance and nature of parallel and series, which would help me to understand the nature of problem.

You have a 450 nF capacitor and wish to combine it with one other to make a
combined capacitance of 1.50 µF .
Transcribed Image Text:You have a 450 nF capacitor and wish to combine it with one other to make a combined capacitance of 1.50 µF .
You are given a capacitor C1 (given). You want to add a 2nd capacitor C2 (unknown) to
give an equivalent capacitance of Ceq (given). Ceq is greater than C1, therefore C2 must be
added to C1. The only way this happens if the capacitors are hooked in parallel where:
Ceq = C1+ C2
Solving for C2:
C2 = Ceq - C1
Write your answer in uF.
Transcribed Image Text:You are given a capacitor C1 (given). You want to add a 2nd capacitor C2 (unknown) to give an equivalent capacitance of Ceq (given). Ceq is greater than C1, therefore C2 must be added to C1. The only way this happens if the capacitors are hooked in parallel where: Ceq = C1+ C2 Solving for C2: C2 = Ceq - C1 Write your answer in uF.
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