Question 11.b of 19SubmitYou have 150.0 mL of a 0.507 Msolution of Ce(NO3)4.What is the concentration of thenitrate ions in the solution?14C78.9.+/-x 100 Question 11.c of 19SubmitYou have 150.0 mL of a 0.507 Msolution of Ce(NO3)4.If the original solution wasdiluted to 350.0 mL, what wouldbe the new concentration of theCe(NO3), in the solution?414C78.9.+/-x 100

11. b. One mole of Ce(NO3)4 contains 4 mol of nitrate ions : Ce(NO3)4 ---> Ce4+ + 4NO3 - Molarity…

Answered: You have 150.0 mL of a 0.507 M solution…

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You have 150.0 mL of a 0.507 M solution of Ce(NO3)4. What is the concentration of the nitrate ions in the solution?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question 11.c of 19
Submit
You have 150.0 mL of a 0.507 M
solution of Ce(NO3)4.
If the original solution was
diluted to 350.0 mL, what would
be the new concentration of the
Ce(NO3), in the solution?
4
1
4
C
7
8.
9.
+/-
x 100

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