You flipped a coin 300 times, and observed that the coin landed heads up 210 times. Use the point estimator from the study to find the sample size necessary for an 80% confidence interval to specify the proportion to within ±0.01. Round the value up to the next integer.

You flipped a coin 300 times, and observed that the coin landed heads up 210 times. Use the point estimator from the study to find the sample size necessary for an 80% confidence interval to specify the proportion to within ±0.01. Round the value up to the next integer.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Of 500 random people surveyed, 72 were smokers. Find the 95% confidence interval. SE=0.0157

Q: A geologist examine 16 seawater samples for mercury concentration. The main mercury concentration…

Q: f n=450 and X = 360, construct a 99% confidence interval.

Q: Suppose we wanted to estimate the average amount of sleep (in hours) a college student gets a night.…

A: Confidence interval : Confidence interval is a range of values it contains the true population…

Q: If n = 108, a = 29 and o = 2.6, construct a 91% confidence interval. Give your answers to three…

A: Since we know population standard deviation, use z-distribution to find z-critical value.…

Q: Construct a confidence interval for the mean of the paired differences for the two populations with…

A: Solution: From the given information, n=32, d-bar=1.358, α=0.05 and sd=0.635.

Q: If n = 220,p = 0.4,then what will be the 87.4% confidence interval for the population proportion?

Q: You measure 35 randomly selected textbooks' weights, and find they have a mean weight of 63 ounces.…

Q: A research scientist wants to know how many times per hour a certain strand of bacteria reproduces.…

Q: sample of 97 psychology graduates found an average salary of $71 K/year. Assume ?=$14 K/year. Find…

A: Given Z score 90% confidence interval=1.645 Sigma=14 n=97

Q: Find the following. Enter your answer rounded to at least two decimals. Z(a/2) for the 92%…

A: Answer: From the given data, 92%confidence interval,

Q: The mean amount of money spent per week on gas by a sample of 32 Oxford drivers was found to be…

A: The sample size is 32, the sample mean is 32.38 and the sample standard deviation is 2.63.

Q: Suppose you want to construct a confidence interval with a margin of error of 0.03 (3%). Find the…

A: The formula for calculating sample size is, n = z2*p^(1-p^)MOE2 Where, z is the z score (default…

Q: Identify the t-score for a 90% confidence interval if the sample size is 25. t = The answer isnt…

A: We have given that Confidence level (c) = 90% = 0.90 Significance level (α) = 1 - c = 1 - 0.90 =…

Q: A 95% confidence interval was found to be (14.312, 21.432). What is the margin of error? ME=

A: Answer: From the given data, 95% confidence interval was found to be (14.312, 21.432) lower limit =…

Q: A sample of 50 students was taken from the local university. These students spent an average of R170…

A: Given information- Sample size (n) = 50 Mean x̅ = R170 Standard deviation (s) = R25.50 Significance…

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: Last year your professor taught economics courses to N = 200 students. From this group you randomly…

Q: You measure 37 randomly selected textbooks' weights, and find they have a mean weight of 63 ounces.…

A: Formula :

Q: Latasha is a waitress at Seventh Heaven Hamburgers. She wants to estimate the average amount each…

Q: Out of 300 people sampled, 24 had kids. Based on this, construct a 95% confidence interval for the…

Q: In a group of 20 health insurance policyholders diagnosed with cancer, each policyholder has…

A: Variance is the measure of dispersion. It is calculated by taking square deviation of each…

Q: If n = 530 and X = 424, construct a 99% confidence interval for the population proportion, p. Give…

Q: Construct the 99.8% confidence interval for the difference P1 - P2 when x, = 23, n, = 53, x2 = 15,…

Q: A sample of 1100 observations taken from a population produced a sample proportion of 0.36 . Make a…

A: Given information Sample proportion = 0.36 Sample size (n) = 1100

Q: If n = 220 and X = 176, construct a 95% confidence interval for the population proportion, p. Give…

Q: A random sample of 49 drivers used on average 753 gallons of gasoline per year. The standard…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: Find the sample size of American adults you would need to predict the results of an election with a…

Q: In the sampling distribution of the mean, the sample mean is considered to be a random variable.…

A: Yes the sampling distribution of the mean is considered to be a random variable . As per central…

Q: If n = 100 and p̂ (p-hat) = 0.4, construct a 95% confidence interval.

A: To find the 95% confidence interval for the population proportion. Given that,…

Q: Construct a 90% confidence interval for the mean when x̅=50 and there are 31 observations. Suppose…

Q: You measure 49 dogs' weights, and find they have a mean weight of 72 ounces. Assume the population…

Q: Suppose we wish to construct a 95% confidence interval for the population proportion of fans in…

A: Given that, Total fans = 200 130 answered yes 95% confidence level

Q: and X = 96, construct a 90% confidence interval for the population proportion, p. Give your answers…

A: Given X=96 N=120

Q: identify the t-score for a 90% confidence interval if the sample size is 31. t=

Q: If n = 220, p-hat = 0.4, then what will be the 90% Confidence Interval for the population…

Q: Out of 500 people sampled, 145 received flu vaccinations this year. Based on this, construct a 90%…

A: We have given that Sample size n=500 , favorable cases x=145 90% confidence interval Sample…

Q: Find the margin of error at a 80% confidence level for estimating the population mean if n = 31, 2 =…

A: According to given question, We have :- Sample size n= 31Sample standard deviation s = 5Sample…

Q: You are comparing men and women on hours spent watching TV. You pick a sample of 12 men and 14 women…

Q: How many Biology students’ records need to be sampled to estimate the percentage who earn "A"s to…

A: The proportion is not provided therefore in worst case it can be assume as (p) 0.5. Margin of error…

Question

You flipped a coin 300 times, and observed that the coin landed
heads up 210 times.

Use the point estimator from the study to find the sample size necessary for an 80% confidence interval to specify the proportion to within ±0.01. Round the value up to the next integer.

Definition Definition Number of subjects or observations included in a study. A large sample size typically provides more reliable results and better representation of the population. As sample size and width of confidence interval are inversely related, if the sample size is increased, the width of the confidence interval decreases.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given data :

VIEW

Step 2: Finding sample size :

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 10 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
In a survey, the planning value for the population proportion is p* 0.25. How large a sample should be taken to provide a 95% confidence interval with a margin of error of 0.02? Round your answer up to the next whole number. =
Find the margin of error at a 80% confidence level for estimating the population mean if n = 15, x = 44 and 8 = 10. Round your answer to 2 decimal places.
If your target population is 123, how many samples do you need for a sampling error of .05 and a level of confidence of 95 percent (.05 level)? Show your solution.
A random sample of high school students is used to estimate the mean time all high school students study for Algebra II tests. A 99% confidence interval based on this sample is: 1.7 hours to 3.1 hours. What is the sample mean?
Identify the t-score for a 95% confidence interval if the sample size is 15. t = the answer isnt 2.131 so what is the answer?
Construct a 96% confidence interval if x=75 and n=200. Round your answers to 3 decimal places.
Find the following. Enter your answer rounded to at least two decimals. z a/2 for the 97% confidence interval
If n = 110 and X = 88, construct a 99% confidence interval for the population proportion, p.Give your answers to three decimals < p <
Find the margin of error at a 80% confidence level for estimating the population mean if n = 16, = 32 and s = 10. Round your answer to 2 decimal places.
Identify the t score for a 99% confidence interval if the sample size is 35 t=
In a survey of a random sample of 49 college students, the sample mean time per week spent watching videos via smart devices was 21 hours and the standard deviation was 6.2 hours. Find the margin of error (E) of the 95% confidence interval for the mean time per week spent by college students watching videos via smart devices. Round your answer to two decimal places.