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You flip a weighted coin that comes up Heads 40% of the time and Tails 60%. If you flip this coin 5 times, what is the probability that you see at least 3 Tails, rounded to the nearest percent? Please input your answer as a decimal rounded to the nearest hundredth. and lallinan that is 20% to he chorn, 20% to ho strawhorns and 50% to he

You flip a weighted coin that comes up Heads 40% of the time and Tails 60%. If you flip this coin 5 times, what is the probability that you see at least 3 Tails, rounded to the nearest percent? Please input your answer as a decimal rounded to the nearest hundredth. and lallinan that is 20% to he chorn, 20% to ho strawhorns and 50% to he

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Hi the correct answer is 0.68, can you tell me why I don’t have to include p(x=1) and p(x=2) in my equation? (As shown in first photo)
0:15 Mon 5 Dec xRights Issue Ques... X no Q2 Heads = 0.4 Tails = 0.6 n = S SIG_-_Practice_Mettl_Problems 2 ✓ x Rights issues 3 wwe LOIRI www 5. You flip a weighted coin that comes up Heads 40% of the time and Tails 60%. If you flip this coin 5 times, what is the probability that you see at least 3 Tails, rounded to the nearest percent? Please input your answer as a decimal rounded to the nearest hundredth. X ad lallinan that is 20% to he chern 20% to ho strawhorny and 50% to ha Q3 P = 0.6 X denotes the no. of tails in a x = Binomial (5,0.60) BINOMIAL DISTRIBUTION P(x-x) = (^cx) p² (1-p) ^-- n-x throw x=0,1,₁2 P(x = 1) = 50₁(0.6) (0.4) 4 = 0.0768 P(x = 2) = 5c2(0.6)2 (0.21)3=0.2304 P(x = 3) = 5c3(0.6) ³ (0.4)² = 0.3456 P(x = 4) = 5c4 (0.6)" (0.4)' = 0.2592 P(x = 5) = 5c5(0.6) (0.4)⁰° = 0.0777 0.98976 + . 19% x SIG_-_Practic |
Transcribed Image Text:0:15 Mon 5 Dec xRights Issue Ques... X no Q2 Heads = 0.4 Tails = 0.6 n = S SIG_-_Practice_Mettl_Problems 2 ✓ x Rights issues 3 wwe LOIRI www 5. You flip a weighted coin that comes up Heads 40% of the time and Tails 60%. If you flip this coin 5 times, what is the probability that you see at least 3 Tails, rounded to the nearest percent? Please input your answer as a decimal rounded to the nearest hundredth. X ad lallinan that is 20% to he chern 20% to ho strawhorny and 50% to ha Q3 P = 0.6 X denotes the no. of tails in a x = Binomial (5,0.60) BINOMIAL DISTRIBUTION P(x-x) = (^cx) p² (1-p) ^-- n-x throw x=0,1,₁2 P(x = 1) = 50₁(0.6) (0.4) 4 = 0.0768 P(x = 2) = 5c2(0.6)2 (0.21)3=0.2304 P(x = 3) = 5c3(0.6) ³ (0.4)² = 0.3456 P(x = 4) = 5c4 (0.6)" (0.4)' = 0.2592 P(x = 5) = 5c5(0.6) (0.4)⁰° = 0.0777 0.98976 + . 19% x SIG_-_Practic |
ghts Issue Ques... X Q2 .WC LOIRIE STUn any X Rights issues 3 Heads = 0.4 Tails = 0.6 S T S. You flip a weighted coin that comes up Heads 40% of the time and Tails 60%. If you flip this coin 5 times, what is the probability that you see at least 3 Tails, rounded to the nearest percent? Please input your answer as a decimal rounded to the nearest hundredth. Q3 Lolding and fallinon that is 20% to he chern 20% to he strawhern and 50% to he BINOMIAL DISTRIBUTION = S .b X denotes the no. of tails in a throw X = Binomial (5,0.60) P(x = x) = (^Cx) p² (1 -p) ^-x = x=0,1₁2 P(x-1)= SCI(0.6) (0.4)" = 0.0768 p ( x = 2) = 5cz (0.6) (0.4) = 0.2304 ² ³ P(x = 3) = Sc3(0.6) ³ (0.4)² P(x = 4) = 5c4 (0.6) 4 (0.4)' = 0.2592 P(x = 5) = Sc5(0.6) (0.4)⁰ = 0.0777 0.3456 0.6825 SI
Transcribed Image Text:ghts Issue Ques... X Q2 .WC LOIRIE STUn any X Rights issues 3 Heads = 0.4 Tails = 0.6 S T S. You flip a weighted coin that comes up Heads 40% of the time and Tails 60%. If you flip this coin 5 times, what is the probability that you see at least 3 Tails, rounded to the nearest percent? Please input your answer as a decimal rounded to the nearest hundredth. Q3 Lolding and fallinon that is 20% to he chern 20% to he strawhern and 50% to he BINOMIAL DISTRIBUTION = S .b X denotes the no. of tails in a throw X = Binomial (5,0.60) P(x = x) = (^Cx) p² (1 -p) ^-x = x=0,1₁2 P(x-1)= SCI(0.6) (0.4)" = 0.0768 p ( x = 2) = 5cz (0.6) (0.4) = 0.2304 ² ³ P(x = 3) = Sc3(0.6) ³ (0.4)² P(x = 4) = 5c4 (0.6) 4 (0.4)' = 0.2592 P(x = 5) = Sc5(0.6) (0.4)⁰ = 0.0777 0.3456 0.6825 SI
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