You conduct an analysis of variance (ANOVA). Suppose that the means u; are very different acrossWhich of the following is true?all groups G= 1,2,..., k). You calculate the statistic F =MSTRMSEO The numerator (MSTR) is likely to be large, making it more likely to reject the null hypothesisO The numerator (MSTR) is likely to be small, making it less likely to reject the null hypothesisO The numerator (MSTR) is likely to be small, making it more likely to reject the null hypothesisO The numerator (MSTR) is likely to be large, making it less likely to reject the null hypothesis

It is given that the means μj are very different across all groups and then you calculate the…

Answered: You conduct an analysis of variance…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The aim of a study is to test the ratio of variances in the weight of two groups of rats being under a certain drugs A ( group 1) and B ( group 2) . A random sample of 16 rats was selected from group land 13 rats from group 2, Then their weight were recorded. The results are shown in the following table n Mean Median sd group 1 16 3.5 3.0 1.05 group 2 13 2.20 2.0 1.15 F15,12,0.05 =0.404 F19,16,0.025 = 0.386| F16,10,0.025 =0.335 F16,10,0.05 =0.401| F15,12,0.1 = 0.496 | F19,16,0.05 =0.451 F10,16,0.025 =0.286 F12,15,0.05 =0.382 F16,19,0.025 =0.371 F10,16,0.05 =0.354 F12,15,0.1=0.475 F16,19,0.05 = 0.437 Construct a 95% confidence interval for the ratio of the variances. [ Hint: because of the rounding select the closest interval ] O a. None of these O b. [ 2.488, 0.238 ] O c. [ 2.160 , 0.309 ] O d. [2.063 , 0.318]
The aim of a study is to test the ratio of variances in the weight of two groups of rats being under a certain drugs A ( group 1) and B ( group 2) . A random sample of 16 rats was selected from group land 13 rats from group 2, Then their weight were recorded. The results are shown in the following table n Mean Median sd group 1 16 3.5 3.0 1.05 group 2 13 2.20 2.0 1.15 F15,12,0.05 = 0.404 F 19,16,0.025 = 0.386 F16,10,0.025 =0.335| F16,10,0.05 =0.401 F15,12,0.1 =0.496 F19,16,0.05 =0.451 F10,16,0.025 = 0.286 F 12,15,0.05 =0.382 F16,19,0.025 = 0.371| F10,16,0.05 = 0.354 F12,15,0.1 =0.475 F16,19,0.05 = 0.437| Construct a 95% confidence interval for the ratio of the variances. [ Hint: because of the rounding select the closest interval ] O a. None of these O b. [ 2.488, O0.238 ] O c. [ 2.160 , 0.309] O d. [2.063 , 0.318]
Incorrect. The weight of boxes of candy is a normal random variable with mean and variance 1/10 pound2. The prior distribution for u is normal with mean 5.01 pound, and variance 1/25 pound2. A random sample of 9 boxes gives a sample mean of x = 5.02 pound. Find the Bayes estimate of u. Round your answer to three decimal places. ji i 5.015
When using an Analysis of Variance test, in order to find out which specific means are different from one another which test is used? a. t-test b. post hoc test c. Cohen’s D test d. Chi-square test
4 4G I. moodle.unizwa.edu.om a | Quiz3 Time left 0:00:21 Question 3 Answer saved Marked out of 2.00 P Flag question Which one of the following choices describes a problem for which an analysis of variance would be appropriate? O A. Comparing the proportion of successes for three different treatments of anxiety. Each treatment is tried on 100 patients O B. Analyzing the relationship between high school GPA and college GPA O . Analyzing the relationship between gender and opinion about capital punishment (favor or oppose). O D. Comparing the mean birth weights of newborn babies for three different hospitals. O E. None of these Clear my choice Previous page Next page 1 2w-ANOVA(3) Jump to... Quiz navigation 7 +
please send correct answer for Q4
Two classes in business statistics showed the following results on a recent test. Class 1 /Class 2 Sample size 25 /21 Sample mean 82/ 84 Sample standard deviation 6.2/ 7.6 Carry out a test to determine whether the difference in the variance of the scores on this test is due to chance variation or is statistically significant with a 0.02 level of significance.
Which outcome is expected if the null hypothesis is true for an analysis of variance? a. SSbetween should be about the same size as SStotal. b. SSbetween should be about the same size as SSwithin. c. MSbetween should be about the same size as MStotal. d. MSbetween should be about the same size as MSwithin.
Is psychiatric history dependent on where the mother lives (country or city)? The test statistics for this hypothesis test are.... How to run t-test? which variable goes where? I attached images, is that correct and where to get the t statistic and p-value?

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