You can calculate the P-value for a chi-square test using technology. After calculating the standardized test statistic, use the cumulative distribution function (CDF) to calculate the area under the curve, Use the P-value method to test the claim. A hospital spokesperson claims that the standard deviation of the waiting times experienced by patients in its minor emergency department is no more than 0.5 minutes. A random sample of 23 waiting times has a standard deviation of 0.7 minutes. At a = 0.05, is there enough evidence to reject the spokesperson's claim? Identify the null and alternative hypotheses. OA. Ho: os0.5 O B. Ho: o<0.5 H:o>0.5 Haio20.5 OC. Ho: o20.5 O D. Ho:o>0.5 Hio<0.5 Haios0.5 Identify the standardized test statistic. y2 = (Round to two decimal places as needed.) Identify the P-value. P= (Round to four decimal places as needed.) Choose the correct conclusion below. O A. Reject Ho. There is not enough evidence at the 5% level of significance to reject the spokesperson's claim. O B. Reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim. OC. Fail to reject Ho. There is not enough evidence at the 5% level of significance to reject the spokesperson's claim. OD. Falil to reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim.

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You can calculate the P-value for a chi-square test using technology. After calculating the standardized test statistic, use the cumulative distribution function (CDF) to
calculate the area under the curve. Use the P-value method to test the claim.
A hospital spokesperson claims that the standard deviation of the waiting times experienced by patients in its minor emergency department is no more than 0.5 minutes. A
random sample of 23 waiting times has a standard deviation of 0.7 minutes. At a = 0.05, is there enough evidence to reject the spokesperson's claim?
Identify the null and alternative hypotheses.
O A. Ho: os0.5
O B. Ho:o<0.5
H:o>0.5
Haio20.5
OC. Ho: o20.5
O D. Ho:o>0.5
Hg:o<0.5
Haios0.5
Identify the standardized test statistic.
x2 = (Round to two decimal places as needed.)
Identify the P-value.
P3D
(Round to four decimal places as needed.)
Choose the correct conclusion below.
O A. Reject Ho- There is not enough evidence at the 5% level of significance to reject the spokesperson's claim.
O B. Reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim.
O C. Fail to reject Ho. There is not enough evidence at the 5% level of significance to reject the spokesperson's claim.
O D. Fail to reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim.
Transcribed Image Text:You can calculate the P-value for a chi-square test using technology. After calculating the standardized test statistic, use the cumulative distribution function (CDF) to calculate the area under the curve. Use the P-value method to test the claim. A hospital spokesperson claims that the standard deviation of the waiting times experienced by patients in its minor emergency department is no more than 0.5 minutes. A random sample of 23 waiting times has a standard deviation of 0.7 minutes. At a = 0.05, is there enough evidence to reject the spokesperson's claim? Identify the null and alternative hypotheses. O A. Ho: os0.5 O B. Ho:o<0.5 H:o>0.5 Haio20.5 OC. Ho: o20.5 O D. Ho:o>0.5 Hg:o<0.5 Haios0.5 Identify the standardized test statistic. x2 = (Round to two decimal places as needed.) Identify the P-value. P3D (Round to four decimal places as needed.) Choose the correct conclusion below. O A. Reject Ho- There is not enough evidence at the 5% level of significance to reject the spokesperson's claim. O B. Reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim. O C. Fail to reject Ho. There is not enough evidence at the 5% level of significance to reject the spokesperson's claim. O D. Fail to reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim.
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