You can calculate the P-value for a chi-square test using technology. After calculating the standardized test statistic, use the cumulative distribution function (CDF) to calculate the area under the curve. Use the P-value method to test the claim. A hospital spokesperson claims that the standard deviation of the waiting times experienced by patients in its minor emergency department is no more than 0.5 minutes. A random sample of 23 waiting times has a standard deviation of 0.6 minutes. At a = 0.10, is there enough evidence to reject the spokesperson's claim? .... Identify the null and alternative hypotheses. B. Ho:os0.5 Haio >0.5 O A. Ho: o20.5 Hai o<0.5 OC. Ho: o<0.5 O D. Ho: o>0.5 Hại o20.5 Haios0.5 Identify the standardized test statistic. x2 =(Round to two decimal places as needed.)

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You can calculate the P-value for a chi-square test using technology. After calculating the standardized test statistic, use the cumulative distribution function (CDF) to
calculate the area under the curve. Use the P-value method to test the claim.
A hospital spokesperson claims that the standard deviation of the waiting times experienced by patients in its minor emergency department is no more than 0.5 minutes. A
random sample of 23 waiting times has a standard deviation of 0.6 minutes. At a = 0.10, is there enough evidence to reject the spokesperson's claim?
Identify the null and alternative hypotheses.
O A. Ho: o20.5
B. Ho:os0.5
Hai o > 0.5
Hạio<0.5
O C. Ho: o<0.5
O D. Ho:o>0.5
Haio20.5
Haios0.5
Identify the standardized test statistic.
x2 =
(Round to two decimal places as needed.)
Transcribed Image Text:You can calculate the P-value for a chi-square test using technology. After calculating the standardized test statistic, use the cumulative distribution function (CDF) to calculate the area under the curve. Use the P-value method to test the claim. A hospital spokesperson claims that the standard deviation of the waiting times experienced by patients in its minor emergency department is no more than 0.5 minutes. A random sample of 23 waiting times has a standard deviation of 0.6 minutes. At a = 0.10, is there enough evidence to reject the spokesperson's claim? Identify the null and alternative hypotheses. O A. Ho: o20.5 B. Ho:os0.5 Hai o > 0.5 Hạio<0.5 O C. Ho: o<0.5 O D. Ho:o>0.5 Haio20.5 Haios0.5 Identify the standardized test statistic. x2 = (Round to two decimal places as needed.)
Identify the standardized test statistic.
x? =
(Round to two decimal places as needed.)
Identify the P-value.
P=
(Round to four decimal places as needed.)
Choose the correct conclusion below.
Reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim.
3. Fail to reject Ho. There is not enough evidence at the 5% level of significance to reject the spokesperson's claim.
Reject Ho-
There is not enough evidence at the 5% level of significance to reject the spokesperson's claim.
Fail to reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim.
Transcribed Image Text:Identify the standardized test statistic. x? = (Round to two decimal places as needed.) Identify the P-value. P= (Round to four decimal places as needed.) Choose the correct conclusion below. Reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim. 3. Fail to reject Ho. There is not enough evidence at the 5% level of significance to reject the spokesperson's claim. Reject Ho- There is not enough evidence at the 5% level of significance to reject the spokesperson's claim. Fail to reject Ho. There is enough evidence at the 5% level of significance to reject the spokesperson's claim.
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