you calculate the probablity of an outcome occuring and get 1.0. What conclusion can you draw? (a) you have made an error. (b) you cannot tell anything without also knowing the probabilty of the outcome NOT occuring. (c) There is a very good chance that the event will occur. (d)There is only a slim chance that the event will occur. (e) The event is certain to occur.

you calculate the probablity of an outcome occuring and get 1.0. What conclusion can you draw? (a) you have made an error. (b) you cannot tell anything without also knowing the probabilty of the outcome NOT occuring. (c) There is a very good chance that the event will occur. (d)There is only a slim chance that the event will occur. (e) The event is certain to occur.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(d) Identify any unusual events. Explain. O A. The event in part (b) is unusual because its probability is less than 0.05. B. The event in part (a) is unusual because its probability is less than 0.05. O c. The event in part (c) is unusual because its probability is less than 0.05. OD. There are no unusual events, because all of the probabilities are greater than 0.05.
Suppose we know that the probabilities P(A) = .5, P(B|A) = .3 and P(A or B) =.3. What is the value for P(A and B)? What is the value for P(B)?
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From an example in real life, give the probabilities of two events and the probability of both events occurring. Based on these events, phrase a question about a conditional probability
For each set of probabilities, determine whether the events A and B are independent or dependent. (If necessary, consult a list of formulas.) Probabilities Independent Dependent = P(A 18) - 1 (a) P(A)=-;P(B) =;P(A\B) = 5 1 1 P(A) =;P (B) = P(A and B) = %3D 4 6. 1 1 P (B|A) = 1 (c) P(4)-극: P(B)-P(Bl4): %3D %3D 1 1 (d) P(A) = : P(B) = P(4 |B) = | %3D
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5
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