You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. Unfortunately the archer stands on an elevated platform of unknown height. However, you find the arrow stuck in the ground 58.0 m away, making a 3.00 angle with the ground Part A How fast was the arrow shot? Hint: In this question, you do not need to know the initial y-position of the arrow, nor should you assume a value. . The final direction of the arrow indicates the ratio of the v_y/v_x. So tan(final_angle with respect to the x-axis)= v_y/v_x but neither v_y, nor v_x are known. Since the arrow initially was fired horizontally, it only has an x component of velocity at first, and since there is no acceleration in x, v_x final= v_x initial. So you only need to find v_x final to get the initial velocity. You need another equation that relates v_y and v_x. Well, v_y -gt and you can get t from v_x*t=(displacement in x). Use the last two equation to eliminate t, which is not required for this problem, which give another equation that involves v_y and v_x. ΑΣφ ? m/s Request Answer Submit Provide Feedback Next

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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You are watching an archery tournament when you
start wondering how fast an arrow is shot from the
bow. Remembering your physics, you ask one of
the archers to shoot an arrow parallel to the
ground. Unfortunately the archer stands on an
elevated platform of unknown height. However, you
find the arrow stuck in the ground 58.0 m away,
making a 3.00 angle with the ground
Part A
How fast was the arrow shot?
Hint: In this question, you do not need to know the initial y-position of the arrow, nor should you assume a
value. . The final direction of the arrow indicates the ratio of the v_y/v_x. So tan(final_angle with respect to
the x-axis)= v_y/v_x but neither v_y, nor v_x are known. Since the arrow initially was fired horizontally, it only
has an x component of velocity at first, and since there is no acceleration in x, v_x final= v_x initial. So you
only need to find v_x final to get the initial velocity. You need another equation that relates v_y and v_x. Well,
v_y -gt and you can get t from v_x*t=(displacement in x). Use the last two equation to eliminate t, which is
not required for this problem, which give another equation that involves v_y and v_x.
ΑΣφ
?
m/s
Request Answer
Submit
Provide Feedback
Next
Transcribed Image Text:You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. Unfortunately the archer stands on an elevated platform of unknown height. However, you find the arrow stuck in the ground 58.0 m away, making a 3.00 angle with the ground Part A How fast was the arrow shot? Hint: In this question, you do not need to know the initial y-position of the arrow, nor should you assume a value. . The final direction of the arrow indicates the ratio of the v_y/v_x. So tan(final_angle with respect to the x-axis)= v_y/v_x but neither v_y, nor v_x are known. Since the arrow initially was fired horizontally, it only has an x component of velocity at first, and since there is no acceleration in x, v_x final= v_x initial. So you only need to find v_x final to get the initial velocity. You need another equation that relates v_y and v_x. Well, v_y -gt and you can get t from v_x*t=(displacement in x). Use the last two equation to eliminate t, which is not required for this problem, which give another equation that involves v_y and v_x. ΑΣφ ? m/s Request Answer Submit Provide Feedback Next
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