You are testing the claim that the mean GPA of night studentsis different than the mean GPA of day students.You sample 55 night students, and the sample mean GPA is2.82 with a standard deviation of 0.76You sample 50 day students, and the sample mean GPA is 2.77with a standard deviation of 0.38Calculate the test statistic, rounded to 2 decimal places

Given that Claim : The mean GPA of night students is different from mean GPA of day students.…

Answered: You are testing the claim that the mean…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 20 night students, and the sample mean GPA is 2.85 with a standard deviation of 0.86. You sample 30 day students, and the sample mean GPA is 3.02 with a standard deviation of 0.4. Test the claim using a 5% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses?H0: = H1: Based on the hypotheses, find the following:Test Statistic = p− value = The correct decision is to The correct summary would be: that the mean GPA of night students is different from the mean GPA of day students.
You hypothesize that people in stats classes are happier than people in all other classes. You compare happiness scores in three of your classes: Statistics, Developmental Psychology, and Social Psychology. In Statistics there are 15 students and the mean happiness rating is 23.1 with a standard deviation of 9.78. In Developmental Psychology there are 15 students and the mean happiness rating is 24.4 with a standard deviation of 2.92. In Social Psychology there are 15 students with a mean rating of 17.7 and standard deviation of 8.46. The sum of squares between groups is equal to 384. The sum of squares within groups is equal to 2461. Use the One-Way ANOVA calculation table to help calculate. What is the degrees of freedom within samples?
You have a sample of 48 randomly selected Vancouverites. On average (the sample mean), the people in your sample spent 425 hours eating food in 2020. The least time a person in the sample spent eating food in 2020 is 367 hours and the most time a person in the sample spent eating food in 2020 is 484 hours. What would be your best guess about the population standard deviation of the time a Vancouverite spent eating food in 2020? Give the number and explain (including assumptions you make about the population distribution).
Mario's weekly poker winnings have a mean of $353 and a standard deviation of $67. Last week he won $185. How many standard deviations from the mean is that?
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 20 night students, and the sample mean GPA is 2.94 with a standard deviation of 0.8. You sample 55 day students, and the sample mean GPA is 2.56 with a standard deviation of 0.44. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. What are the correct hypotheses? Based on the hypotheses, find the following:Test Statistic = Critical Values = ±
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 35 night students, and the sample mean GPA is 2.91 with a standard deviation of 0.97. You sample 20 day students, and the sample mean GPA is 2.99 with a standard deviation of 0.82. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAS are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses? Ho: M₁ H₁: M₁ Test Statistic = Critical Values = = ± H₁₂ Based on the hypotheses, find the following: ≠v H₂ OF (Just enter the positive CV.) The correct decision is to Fail to reject the null hypothesis The correct summary would be: There is not enough evidence to support the claim ✓ of night students is different from the mean GPA of day students. o that the mean GPA
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 night students, and the sample mean GPA is 2.83 with a standard deviation of 0.94. You sample 55 day students, and the sample mean GPA is 2.97 with a standard deviation of 0.92. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses?H0: Select an answer μ σ² μ₂ p μ₁ x̄₂ s² x̄₁ = Select an answer μ x̄₂ σ² μ₂ x̄₁ μ₁ s² p H1: Select an answer σ² μ x̄₁ s² p x̄₂ μ₁ μ₂ ? = < > ≤ ≠ ≥ Select an answer μ x̄₂ x̄₁ μ₂ σ² s² μ₁ p Based on the hypotheses, find the following:Test Statistic = Critical Values = ±± (Just enter the positive CV.)The correct decision is to Select an answer Reject the null hypothesis Fail to reject the null hypothesis The correct summary would be: Select an answer There is not enough…
A successful basketball player has a height of 6 feet 11 inches, or 211 cm. Based on statistics from a data set, his height converts to the z score of 5.17. How many standard deviations is his height above the mean?
Parents of teenage boys often complain that auto insurance costs more, on average, for teenage boys than for teenage girls. A group of concerned parents examines a random sample of insurance bills. The mean annual cost for 36 teenage boys was $672. For 23 teenage girls, it was $559. From past years, it is known that the population standard deviation for each group is $180. Determine whether or not you believe that the mean cost for auto insurance for teenage boys is greater than that for teenage girls. Conduct a hypothesis test at the 5% level. State the distribution to use for the test. (Round your answers to two decimal places.) What is the test statistic? (If using the z distribution round your answer to two decimal places, and if using the t distribution round your answer to three decimal places.) What is the p-value? (Round your answer to four decimal places.) i. ii. ii.
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 60 night students, and the sample mean GPA is 2.83 with a standard deviation of 0.52. You sample 50 day students, and the sample mean GPA is 3.21 with a standard deviation of 0.65. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAS are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses? Ho: (H, H, H1: [H, Based on the hypotheses, find the following: Test Statistic = -3.3161 Critical Values = +2.576 X (Just enter the positive CV.)
A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 250 students in evening classes and finds that they have a mean test score of 86.6. He knows the population standard deviation for the evening classes to be 7.2 points. A random sample of 200 students from morning classes results in a mean test score of 87.8. He knows the population standard deviation for the morning classes to be 4.7 points. Test his claim with a 90% level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.

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You are testing the claim that the mean GPA of night students is different than the mean GPA of day students. You sample 55 night students, and the sample mean GPA is 2.82 with a standard deviation of 0.76 You sample 50 day students, and the sample mean GPA is 2.77 with a standard deviation of 0.38