You are testing the claim that the mean GPA of night students is different than the mean GPA of day students. You sample 55 night students, and the sample mean GPA is 2.82 with a standard deviation of 0.76 You sample 50 day students, and the sample mean GPA is 2.77 with a standard deviation of 0.38
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Q: You are testing the claim that the mean GPA of night students is different from the mean GPA of day…
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Q: You are testing the claim that the mean GPA of night students is different from the mean GPA of day…
A: given data NIGHT STUDENT :x¯1 = 2.44s1 =0.33n1 = 35MBAx¯2 =2.21s2 = 0.45n2 = 60α = 0.05claim : μ1…
Q: Suppose you know the population average wage in the manufacturing industry in the U.S. is $26.72 per…
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A: Given: n1=30x¯1=2.83s1=0.94n2=55x¯2=2.97s2=0.92α=0.01
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- You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 45 night students, and the sample mean GPA is 2.63 with a standard deviation of 0.81. You sample 40 day students, and the sample mean GPA is 3.02 with a standard deviation of 0.59. Test the claim using a 5% level of significance. Assume the population standard deviations are unequal and that GPAS are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses? Ho: M₁ = μ₂ H₁: M₁ Based on the hypotheses, find the following: Test Statistic = -0.7918 X O μ₂ Critical Values=2.0154 x (Just enter the positive CV.) The correct decision is to Reject the null hypothesis The correct summary would be: There is enough evidence to support the claim of night students is different from the mean GPA of day students. o that the mean GPAYou hypothesize that people in stats classes are happier than people in all other classes. You compare happiness scores in three of your classes: Statistics, Developmental Psychology, and Social Psychology. In Statistics there are 15 students and the mean happiness rating is 23.1 with a standard deviation of 9.78. In Developmental Psychology there are 15 students and the mean happiness rating is 24.4 with a standard deviation of 2.92. In Social Psychology there are 15 students with a mean rating of 17.7 and standard deviation of 8.46. The sum of squares between groups is equal to 384. The sum of squares within groups is equal to 2461. Use the One-Way ANOVA calculation table to help calculate. What is the degrees of freedom between samples?The manager of a major retail store has taken a random sample of 25 customers. The average sale was $52.50. The population standard deviation is known to be $6.10. The manager would like to determine whether or not the mean sales by all customers are significantly more than $50. What is the p-value for the test?
- Parents of teenage boys often complain that auto insurance costs more, on average, for teenage boys than for teenage girls. A group of concerned parents examines a random sample of insurance bills. The mean annual cost for 36 teenage boys was $670. For 23 teenage girls, it was $556. From past years, it is known that the population standard deviation for each group is $180. Determine whether or not you believe that the mean cost for auto insurance for teenage boys is greater than that for teenage girls. Conduct a hypothesis test at the 5% level.NOTE: If you are using a Student's t-distribution for the problem, including for paired data, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) Part (a) State the null hypothesis. H0: ?boys > ?girls H0: ?boys = ?girls H0: ?boys < ?girls H0: ?boys ≠ ?girls Part (b) State the alternative hypothesis. Ha: ?boys > ?girls Ha: ?boys ≠ ?girls…You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 20 night students, and the sample mean GPA is 2.85 with a standard deviation of 0.86. You sample 30 day students, and the sample mean GPA is 3.02 with a standard deviation of 0.4. Test the claim using a 5% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses?H0: = H1: Based on the hypotheses, find the following:Test Statistic = p− value = The correct decision is to The correct summary would be: that the mean GPA of night students is different from the mean GPA of day students.You hypothesize that people in stats classes are happier than people in all other classes. You compare happiness scores in three of your classes: Statistics, Developmental Psychology, and Social Psychology. In Statistics there are 15 students and the mean happiness rating is 23.1 with a standard deviation of 9.78. In Developmental Psychology there are 15 students and the mean happiness rating is 24.4 with a standard deviation of 2.92. In Social Psychology there are 15 students with a mean rating of 17.7 and standard deviation of 8.46. The sum of squares between groups is equal to 384. The sum of squares within groups is equal to 2461. Use the One-Way ANOVA calculation table to help calculate. What is the degrees of freedom within samples?
- Mario's weekly poker winnings have a mean of $353 and a standard deviation of $67. Last week he won $185. How many standard deviations from the mean is that?You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 20 night students, and the sample mean GPA is 2.94 with a standard deviation of 0.8. You sample 55 day students, and the sample mean GPA is 2.56 with a standard deviation of 0.44. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. What are the correct hypotheses? Based on the hypotheses, find the following:Test Statistic = Critical Values = ±A newspaper article reports that the mean cost for preventative dental care per year is $175 with a standard deviation of $35 (assume that this is the population standard deviation). You want to test whether the mean cost for preventative dental care in your company is different from what was reported in the article. You take a random sample of 250 employees and find the mean cost is $171. Does this signficantly differ from what was reported in the article? Run the appropriate test at α=0.05. Give each of the following to receive full credit: 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value. You MUST show your work to receive full credit. Partial credit is available.
- You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 35 night students, and the sample mean GPA is 2.91 with a standard deviation of 0.97. You sample 20 day students, and the sample mean GPA is 2.99 with a standard deviation of 0.82. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAS are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses? Ho: M₁ H₁: M₁ Test Statistic = Critical Values = = ± H₁₂ Based on the hypotheses, find the following: ≠v H₂ OF (Just enter the positive CV.) The correct decision is to Fail to reject the null hypothesis The correct summary would be: There is not enough evidence to support the claim ✓ of night students is different from the mean GPA of day students. o that the mean GPAYou are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 night students, and the sample mean GPA is 2.83 with a standard deviation of 0.94. You sample 55 day students, and the sample mean GPA is 2.97 with a standard deviation of 0.92. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses?H0: Select an answer μ σ² μ₂ p μ₁ x̄₂ s² x̄₁ = Select an answer μ x̄₂ σ² μ₂ x̄₁ μ₁ s² p H1: Select an answer σ² μ x̄₁ s² p x̄₂ μ₁ μ₂ ? = < > ≤ ≠ ≥ Select an answer μ x̄₂ x̄₁ μ₂ σ² s² μ₁ p Based on the hypotheses, find the following:Test Statistic = Critical Values = ±± (Just enter the positive CV.)The correct decision is to Select an answer Reject the null hypothesis Fail to reject the null hypothesis The correct summary would be: Select an answer There is not enough…A successful basketball player has a height of 6 feet 11 inches, or 211 cm. Based on statistics from a data set, his height converts to the z score of 5.17. How many standard deviations is his height above the mean?