You are required to prepare an alcohol-based hand sanitizer in a closed container as displayed in Figure 1. The formulation consists of 60 moles % ethanol. Care should be taken as alcohol are flammable. At room temperature, the partial molar volumes for ethanol (1) and water (2) in a 60 mole % ethanol solution are k= 36.3 cm³.mor" and V: =19.7 cm³.mol", respectively. The pure species molar volume for ethanol and water are V= 39.2 and V, =17.7 cm³ mol*", respectively. Determine the volumes of pure ethanol and pure water in a 5 Liter sanitizer mixture at room temperature. (Hint: 1 cm³ = 0.001 L)
You are required to prepare an alcohol-based hand sanitizer in a closed container as displayed in Figure 1. The formulation consists of 60 moles % ethanol. Care should be taken as alcohol are flammable. At room temperature, the partial molar volumes for ethanol (1) and water (2) in a 60 mole % ethanol solution are k= 36.3 cm³.mor" and V: =19.7 cm³.mol", respectively. The pure species molar volume for ethanol and water are V= 39.2 and V, =17.7 cm³ mol*", respectively. Determine the volumes of pure ethanol and pure water in a 5 Liter sanitizer mixture at room temperature. (Hint: 1 cm³ = 0.001 L)
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
![(b) You are required to prepare an alcohol-based hand sanitizer in a closed container as
displayed in Figure 1. The formulation consists of 60 moles % ethanol. Care should be
taken as alcohol are flammable. At room temperature, the partial molar volumes for
ethanol (1) and water (2) in a 60 mole % ethanol solution are V= 36.3 cm³.mol" and V:
=19.7 cm.mol1, respectively. The pure species molar volume for ethanol and water are
V= 39.2 and V =17.7 cm³ mol", respectively.
Determine the volumes of pure ethanol and pure water in a 5 Liter sanitizer mixture at
room temperature. (Hint: 1 cm³ = 0.001 L)
HAND
SANITISER
Figure 1: 5 Liter hand sanitizer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff873fb19-599c-4c86-9257-a70b547347d9%2F76b9b76e-e887-4270-9037-169468f62c3e%2Fzs8ey8k_processed.png&w=3840&q=75)
Transcribed Image Text:(b) You are required to prepare an alcohol-based hand sanitizer in a closed container as
displayed in Figure 1. The formulation consists of 60 moles % ethanol. Care should be
taken as alcohol are flammable. At room temperature, the partial molar volumes for
ethanol (1) and water (2) in a 60 mole % ethanol solution are V= 36.3 cm³.mol" and V:
=19.7 cm.mol1, respectively. The pure species molar volume for ethanol and water are
V= 39.2 and V =17.7 cm³ mol", respectively.
Determine the volumes of pure ethanol and pure water in a 5 Liter sanitizer mixture at
room temperature. (Hint: 1 cm³ = 0.001 L)
HAND
SANITISER
Figure 1: 5 Liter hand sanitizer
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