You are looking at a map with a scale of 1 inch = 50 miles. If two towns are separated on the map by 6 ​inches, what is the actual distance between​ them? Group of answer choices A) The actual distance between them is 300 miles. Since 1 inch =50 ​miles, 6 inches = 50 ÷ 6 ​miles or 300 miles. B) The actual distance between them is 6 miles. Since 1 inch = 50 ​miles, 6 inches equals 6 x 50 ​miles or 6 miles. C) The actual distance between them is 300 miles. Since 1 inch = 50 ​miles, 6 inches = 6 x 50 ​miles or 300 miles. D) The actual distance between them is 6 miles. The distance between the two towns on the map is the same as the actual distance between them. E) The actual distance between them is 300 kilometers. Since 1 inch = 50 ​miles, 6 inches = 6 x 50 ​inches or 300 inches. F) The distance between them according to the map is approximately 300 ​miles, but the actual distance is harder to calculate because the roads are not necessarily straight and direct.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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You are looking at a map with a scale of 1 inch = 50 miles. If two towns are separated on the map by 6 ​inches, what is the actual distance between​ them?

Group of answer choices

A) The actual distance between them is 300 miles. Since 1 inch =50 ​miles, 6 inches = 50 ÷ 6 ​miles or 300 miles.

B) The actual distance between them is 6 miles. Since 1 inch = 50 ​miles, 6 inches equals 6 x 50 ​miles or 6 miles.

C) The actual distance between them is 300 miles. Since 1 inch = 50 ​miles, 6 inches = 6 x 50 ​miles or 300 miles.

D) The actual distance between them is 6 miles. The distance between the two towns on the map is the same as the actual distance between them.

E) The actual distance between them is 300 kilometers. Since 1 inch = 50 ​miles, 6 inches = 6 x 50 ​inches or 300 inches.

F) The distance between them according to the map is approximately 300 ​miles, but the actual distance is harder to calculate because the roads are not necessarily straight and direct.

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