You are investigating a catabolic pathway in the cell. Refer to the different reactions be Reaction 1: X + Y -> Z + A Reaction 2: A+ B + C -> D + E DG= DG° + RT In (k), assume RT is in the cell at 37°C and equals 0.616 Luckily for you, someone else has already determined the equilibrium concentrations fo [A] = 3, [B] = 2, [C] = 4, [D] = 5, [E] = 2, You have been asked to determine hat the STANDARD Gibbs Free Energy in Texas fo calculations with a minimum of filling in every part of the equation written in FULL above. Natural log bank in case you don't have a calculator In(2.4) = 0.875, In (0.25) = -1.38 In(2) = 0.69 In(0.416) = -0.875, In 0.5 = -0.69, In(4) = 1.38, In(0.777) =-0.25 In(1.285) = 0.25
You are investigating a catabolic pathway in the cell. Refer to the different reactions be Reaction 1: X + Y -> Z + A Reaction 2: A+ B + C -> D + E DG= DG° + RT In (k), assume RT is in the cell at 37°C and equals 0.616 Luckily for you, someone else has already determined the equilibrium concentrations fo [A] = 3, [B] = 2, [C] = 4, [D] = 5, [E] = 2, You have been asked to determine hat the STANDARD Gibbs Free Energy in Texas fo calculations with a minimum of filling in every part of the equation written in FULL above. Natural log bank in case you don't have a calculator In(2.4) = 0.875, In (0.25) = -1.38 In(2) = 0.69 In(0.416) = -0.875, In 0.5 = -0.69, In(4) = 1.38, In(0.777) =-0.25 In(1.285) = 0.25
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The lock-and-key model is used to describe the catalytic enzyme activity, based on the interaction between enzyme and substrate. This model considers the lock as an enzyme and the key as a substrate to explain this model. The concept of how a unique distinct key only can have the access to open a particular lock resembles how the specific substrate can only fit into the particular active site of the enzyme. This is significant in understanding the intermolecular interaction between proteins and plays a vital role in drug interaction.
Question
X is 6 y is 3 z is 2
![You are investigating a catabolic pathway in the cell. Refer to the different reactions be
Reaction 1: X + Y -> Z + A
Reaction 2: A+ B + C -> D + E
DG= DG° + RT In (k), assume RT is in the cell at 37°C and equals 0.616
Luckily for you, someone else has already determined the equilibrium concentrations fo
[A] = 3,
[B] = 2,
[C] = 4,
[D] = 5, [E] = 2,
You have been asked to determine
hat the STANDARD Gibbs Free Energy in Texas fo
calculations with a minimum of filling in every part of the equation written in FULL above.
Natural log bank in case you don't have a calculator
In(2.4) = 0.875,
In (0.25) = -1.38
In(2) = 0.69
In(0.416) = -0.875,
In 0.5 = -0.69,
In(4) = 1.38,
In(0.777) =-0.25
In(1.285) = 0.25](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb0540d8-126b-4df1-bdb3-c8d176e8543c%2F5be90863-8a8e-4717-b434-307d6d09da00%2Fezyrzd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You are investigating a catabolic pathway in the cell. Refer to the different reactions be
Reaction 1: X + Y -> Z + A
Reaction 2: A+ B + C -> D + E
DG= DG° + RT In (k), assume RT is in the cell at 37°C and equals 0.616
Luckily for you, someone else has already determined the equilibrium concentrations fo
[A] = 3,
[B] = 2,
[C] = 4,
[D] = 5, [E] = 2,
You have been asked to determine
hat the STANDARD Gibbs Free Energy in Texas fo
calculations with a minimum of filling in every part of the equation written in FULL above.
Natural log bank in case you don't have a calculator
In(2.4) = 0.875,
In (0.25) = -1.38
In(2) = 0.69
In(0.416) = -0.875,
In 0.5 = -0.69,
In(4) = 1.38,
In(0.777) =-0.25
In(1.285) = 0.25
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