What is the mean, median and mode for the dependent variable?Mean =MedianMode == You are interested in whether level of education influences a person's exposure to the media. You definelow media exposure as 0-5 hours/week, medium exposure as 6-10 hours/week and high exposure as morethan 10 hours/week.You randomly sample 400 adults and find that 175 have a high school education, 140 have college as theirhighest level of education, and 85 have a postgraduate degree (e.g., JD, MA, MPA, DDS, Dr., Ph.D.). Ofthose with a high school education, 72 have low levels of media exposure, 40 have medium levels of mediaexposure, and 63 have high levels of media exposure. Of those with a college degree, 45 have low levelsof media exposure, 45 have medium levels of media exposure, and 50 have high levels of exposure. Finally,of those with a postgraduate degree, 32 have low levels of media exposure, 35 have medium levels of mediaexposure, and 18 have high levels of media exposure.MediaLow (0-5 hrs/wk)Exposure Medium (6-10 hrs/wk)_ _40High (11+ hrs/wk)_Education and Media ExposureTotalHigh School7263175Education LevelCollege454550140Postgraduate32351885Total14120131400

The experiment is aimed to find whether the level of education influences a person's exposure to the media. So, here the variable that is getting effected is person's exposure to the media, which is effected by the level of education. Hence, person's exposure to the media is the dependent variable.The levels of the dependent variable and there frequencies are given as follows: Media Exposure Frequency Low (0-5) 149 Medium (6-10) 120 High (11+ hours) 131 Total 400 The width of the class interval 11+hours will be taken 5 for the sake of regularity of the The frequency distribution table is as follows: Class Interval Class Boundary Frequency(f) Class mark(x) x.f 0-5 -0.5-5.5 149 3 447 6-10 5.5-10.5 120 8 960 11 and above 10.5-15.5 131 13 1703 Mean=∑xf∑f=447+960+1703400=3110400=7.775 For median, consider: Class Boundary Frequency(f) Cumulative frequency -0.5-5.5 149 149 5.5-10.5 120 269 10.5-15.5 131 400 N2=4002=200 Median class = 5.5-10.5 l=5.5, h=5, f=120, cf=149Median=l+N2-cff×h=5.5+200-149120×5=7.625 For Mode, Modal class = -0.5- 5.5 Mode=l+f1-f02f1-f0-f2×h=-0.5+149-02×149-120×5=3.68 Hence, Mean = 7.775 Median = 7.625 Mode = 3.68