You are interested in finding a 90% confidenceinterval for the average number of days of class thatcollege students miss each year. The data below showthe number of missed days for 11 randomly selectedcollege students. Round answers to 3 decimal placeswhere possible.4771631111104a. To compute the confidence interval use a ?0distribution.b. With 90% confidence the population mean numberof days of class that college students miss is betweenanddays.c. If many groups of 11 randomly selected non-residential college students are surveyed, then adifferent confidence interval would be produced fromeach group. Aboutpercent of theseconfidence intervals will contain the true populationmean number of missed class days and aboutpercent will not contain the true populationmean number of missed class days.

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Answered: You are interested in finding a 90%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 27 5 28 22 15 9 16 10 25 18 5 a. To compute the confidence interval use a Z OR T distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between ? and ? visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population mean number of visits per patient and about ? percent will not contain the true population mean number of visits per patient.
Next Question A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and w that the distribution of weights is Normal. Find a 95% confidence interval for the mean weight of all bags of oranges. Use technology for your calculations. Answer parts a and b ley weighed 9.3, 9.1, 9.5, and 9.6 pounds. D Assume below. a. Choose the correct interpretation of the confidence interval below and, if necessary, fill in the answer boxes to complete your choice. O A. We are 95% confident that the sample mean is between and O B. There is a 95% chance that all intervals will be between and O C. We are 95% confident the population mean is between and O D. The requirements for constructing a confidence interval are not satisfied. (Type integers or decimals rounded to the nearest thousandth as needed. Use ascending order.) b. Does the interval capture 10 pounds? Is there enough evidence to reject the null hypothesis that the population mean weight is 10 pounds? Explain…
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Section b
You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 12 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 7 26 5 10 23 14 14 8 19 6 8 12 a. To compute the confidence interval use a ? z or t distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between __and ___visits. c. If many groups of 12 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About __percent of these confidence intervals will contain the true population mean number of visits per patient and about __percent will not contain the true population mean number of visits per patient.
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You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 19 28 12 5 9 8 5 21 20 21 24 9 21 a. To compute the confidence interval use a ____distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between ____ and _____ visits. c. If many groups of 13 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About ______percent of these confidence intervals will contain the true population mean number of visits per patient and about_______ percent will not contain the true population mean number of visits per patient.
You are interested in finding a 90% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 13 randomly selected college students. Round answers to 3 decimal places where possible. 7 8 8 0 2 11 6 10 2 0 1 3 1 With 90% confidence the population mean number of days of class that college students miss is between and days.
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
You are interested in finding a 95% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 7 8 19 14 10 5 15 20 5 27 26 a. To compute the confidence interval use a ? v distribution. b. With 95% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.

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