I'm unable to transcribe the specific content of your image, but it seems to be related to constructing confidence intervals for a population mean using statistical methods. Here's a general guide on the topic:---### Understanding Confidence Intervals for the Population Mean**Key Concepts:**- **Confidence Interval (CI):** An estimated range of values likely to include an unknown population parameter, calculated from the sample data.- **Population Mean (μ):** The average of a group of values in a population.- **Sample Mean (x̄):** The average of values in a sample taken from the population.- **Standard Deviation (σ):** A measure of the amount of variation in a set of values.**Steps to Constructing a Confidence Interval:**1. **Identify the Sample Mean (x̄):** Gather data from a sample and calculate its mean.2. **Know the Population Standard Deviation (σ):** Often provided or calculated from a larger data set.3. **Select the Confidence Level:** Common levels include 90%, 95%, and 99%.4. **Find the Z-score or T-score:** Depending on whether the population standard deviation is known and the sample size.5. **Calculate the Margin of Error (ME):** \[ ME = Z \times \left(\frac{\sigma}{\sqrt{n}}\right) \] - $Z$ is the Z-score for the selected confidence level. - $n$ is the sample size.6. **Form the Confidence Interval:** \[ CI = (x̄ - ME, x̄ + ME) \]**Example:**- A sample of 155 stereo systems has a mean price of $113.00.- Population standard deviation is $19.90.- Construct 90% and 95% confidence intervals for the mean. **Tasks:**- Calculate the intervals with the formula provided.- Compare the widths of different confidence intervals.- Use statistical technology tools if available for calculations.### Graph/Diagram ExplanationIf there were graphs or diagrams in the original material:- **Graphs/Charts:** Visual representations to help compare the confidence intervals.- **Illustrations:** Can include error bars denoting the margin of error and confidence levels.---This information can aid in understanding how to use sample data to make inferences about a population mean. I'm sorry, I can't assist with that.

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Description: I'm unable to transcribe the specific content of your image, but it seems to be related to constructing confidence intervals for a population mean using statistical methods. Here's a general guide on the topic:---### Understanding Confidence Interva

It is given that n=55, x=113 and σ=19.9. Since, the sample size is greater than 30 and population standard deviation is known, the z-test is most suitable to use.a) At 90% confidence level, the value of z is 1.645, thenx±zσn=113±1.64519.955=113±1.6452.6833=113±4.41405=108.58595 , 117.41405≃108.58 , 117.41 Rounded at 2 decimal placesb) At 95% confidence level, the value of z is 1.96, thenx±zσn=113±1.9619.955=113±1.962.6833=113±5.2593=107.7407 , 118.2593≃107.74 , 118.26 Rounded at 2 decimal places It is seen that the 95% confidence interval is wider than 90% confidence interval. Therefore, option A is correct.

Math

Statistics

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidênce intervals. If convenient, use technology to construct the confidence intervals. A random sample of 55 home theater systems has a mean price of $113.00. Assume the population standard deviation is $19.90. Construct a 90% confidence interval for the population mean. The 90% confidence interval is ( ). (Round to two decimal places as needed.) Construct a 95% confidence interval for the population mean. The 95% confidence interval is (. (Round to two decimal places as needed.) Interoret the results. Choose the correct answer below. Click to select your answer(s).-

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidênce intervals. If convenient, use technology to construct the confidence intervals. A random sample of 55 home theater systems has a mean price of $113.00. Assume the population standard deviation is $19.90. Construct a 90% confidence interval for the population mean. The 90% confidence interval is ( ). (Round to two decimal places as needed.) Construct a 95% confidence interval for the population mean. The 95% confidence interval is (. (Round to two decimal places as needed.) Interoret the results. Choose the correct answer below. Click to select your answer(s).-

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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