You are given the null and alternative hypotheses Hg H 2 , and HA HSH together with the sample information to the right Complete parts a and b bolow Sample 1 n13 X 559 528 5 a Assuming that the popiulations are normally distributed with equal variances, test at the 0 10 level of significance whether to reject the null hypothesis the sample information. Use the test statistic approach

Q: 3 -4- -0- 4. 2.

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Q: 8.20+2

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Q: 24 12 XD

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Q: . 3류 - 2층 : 3% +4/3) 1

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Q: 5(18)

A: To find5(18)

Q: 2) 36³x=¹

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Q: 1+3+5+7...+1003

A: Sum of n odd numbers, where the last term of the series is (2n – 1), is, Sn = 1 + 3 + 5 + …. + (2n –…

Q: 6.5+ 4

A: To simplify given

Q: 7/2 + 3 4/6

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Q: 5/14+1/6

A: 514+16=15+742

Q: 33/29 b.

A:

Q: 22n+1 3n+1 2.

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Q: Poove BLO => YQ< B.

A:

Q: FIND S + 4 (s² – 8S + 6) -

A:

Q: 2

A: The Laplace inverse can be found by splitting the expression into three parts as it have power of 3…

Q: 7 2 3k+1= [A] k = 2

A: Consider the equation ∑n=273k+1=A We have to find the value of A Expand the summation of left hand…

Q: 4(5+6)=

A: Given: 4(5+6)=

Q: 6   9,171.6

A:

Q: 81 (1) 420

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Q: 56 10

A: The objective is to evaluate the value for

Q: 4. Fill in the following contingency table with the number of observations that fall into each com-…

A: x1 = number of colored oranges from Skittles brand = 77 x2 = number of colored oranges from M &amp;…

Q: (n + 4)3 =

A: Given query is to expand (n+4)3

Q: 38 10

A:

Q: expansion of (1-2m)“

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Q: 10| 5 10 10 -5 -5

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Q: 18(9+7)+3

A: 18(9+7)+3

Q: 6. 3 (2s+5)³

A:

Q: 29 Using the combination formula expand (5+x)

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Q: 6. Using the data from the contingency table, obtain the value of the test statistic of our test. 7.…

A: Step 1: Given: x1 = number of colored oranges from Skittles brand = 77 x2 = number of colored…

Q: expand (x+y)6

A:

Q: 11.6 - (-12.2) + (11.7)

A: