You are given the following mortality table: 74 0.015 75 0.018 76 0.021 77 0.027 78 0.032 79 0.036 80 0.042 81 0.047 Find 21974:77. (A) 0.05372 (B) 0.05124 (C) 0.05017 (D) 0.04836 (E) 0.04635
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- The expected number of defectives in samples of 200 units taken periodically from the output of a machine that has a 0.5% defective rate is __________. 3 1.5 1 10Age 1950 Population 1950 Mortality Rate per 100,000 1990 Population 1990 Mortality Rate per 100,000 2000 Population 2000 Mortality Rate per 100,000 < 20 15,541,000 11.6 18,926,000 10.5 22,335,000 10.1 20 – 29 18,789,000 23.5 22,335,000 17.8 25,465,000 16.9 30 – 39 11,435,000 43.2 13,123,000 38.7 17,438,000 40.2 40 – 49 8,586,000 115.6 10,809,000 98.8 13,789,000 94.5 50 – 59 6,234,000 310.8 9,120,000 385.8 11,983,000 401.0 60+ 3,749,000 435.0 6,890,000 567.9 9,387,000 785.7 Calculate the direct adjusted mortality rate for both 1950 and 1990 using the 2000 information as the standard. (Hint: Make a table to show the expected number of deaths for each year). Also include the ratio of 1990 mortality rate to 1950 mortality rate.Here is the data 0.75 0.74 0.75 0.84 0.63 0.69 0.83 0.9 0.09 0.4 0.37 0.44 0.85 0.78 0.42 0.91 0.92 0.84 0.91 0.81 0.89 0.37 0.9 0.38 0.45 0.38 0.42 0.82 0.11 0.42 0.39 0.11 0.1 0.84 0.43 0.75 0.37 0.1 0.44 0.25 0.44 0.37 0.58 0.4 0.51 0.8 0.42 0.31 0.44 0.83 0.75 0.93 0.81 0.87 0.78 0.84 0.69 0.61
- SETest for whether there has been a significant change in diabetes incidence over time.Calculate my average exam 1=35 exam 2= 47 exam 3=67 exam 4= 80.625 homework 1b = 95.14 homework 2a= 98.42 homework 2b= 98.36 homework 3a = 97.15 homework 3b= 97.94 homework 4a= 99.49 homework 4b = 97.54 homework 5a= 92.35 homework 5b=92.80 homework 6= 95.71 homework 7a = 94.70 homework 7b = 94.84 homework 8a = 84.86 homework 8b = 94.02 homework 9a= 79.06 Achieve practice 1a= 100 achieve practice 1b= 100 achieve practice 2a =100 achieve practice 2b= 100 achieve practice 3a =100 achieve 3b = 100 achieve practice 4a= 100 achieve practice 5a= 100 achieve practice 5b = 100 achieve practice 6 = 100 achieve practice 7a = 100 achieve practice 7b = 100 achieve practice 8a= 100 achieve practice 8b = 100 achieve practice 9a= 100 achieve practice 9b = 0 recitation= 93
- 9c In Africa in 2011, the number of deaths of a female from cardiovascular disease for different age groups are in the table below ("Global health observatory," 2013). In addition, the proportion of deaths of females from all causes for the same age groups are also in table below. Table: Deaths of Females for Different Age Groups Age 5-14 15-29 30-49 50-69 Total Cardiovascular Frequency 8 16 56 433 513 All Cause Proportion 0.10 0.12 0.26 0.52 Do the data show that the death from cardiovascular disease are in the same proportion as all deaths for the different age groups? Test at the 5% level. (vii) Comparing p-value and α value, which is the correct decision to make for this hypothesis test? A. Reject Ho B. Fail to reject Ho C. Accept Ho D. Accept HA Enter letter corresponding to correct answer. (viii) Select the statement that most correctly interprets the result of this test: A. The result is not statistically…Arsenic Amounts Arkansas 4.80 4.90 5.02 5.37 5.43 5.37 5.60 5.61 5.57 5.91 5.97 6.12 California 1.50 3.71 3.95| 4.45| 4.94| 5.12 5.33 5.35 5.41 5.49 5.56 5.61 Texas 5.57 5.82 6.62 6.90 6.85 6.88 | 7.05 7.34 7.48| 7.58 7.71 | 7.73 IIn a recent Gallup survey of 1,012 randomly selected U.S. adults (age 18 and over), 53% said that they were dissatisfied with the quality of education students receive in kindergarten through grade 12. They also report that the "margin of sampling error is plus or minus 4%" What is the sample being used? R F O U.S. adults (age 18 and over) O 1012 randomly selected U.S. adults OU.S. adults satisfied with K-12 education O U.S. adults dissatisfied with K-12 education C e Textbook and Media Save for Later O % 18 G 7 T Y U O 8 9 TH J K L Attempts: 0 of 1 used 0 Submit Answer 55°F Backsp
- The accompanying data are x = advertising share and y = market share for a particular brand of soft drink during 10 randomly selected years. x 0.104 0.072 0.072 0.077 0.086 0.047 0.060 0.050 0.070 0.052 y 0.137 0.127 0.120 0.086 0.079 0.076 0.065 0.059 0.051 0.039 b)Calculate the equation of the estimated regression line. (Round your answers to four decimal places.) d)Calculate a point estimate of ?e. (Round your answer to five decimal places.)College Algebra Exponential and Logarithmic Equations Activity The risk of having a car accident increases exponentially as the concentration of alcohol in the blood increases. The risk is modeled by R = 6e12.77x where x is the blood alcohol concentration (BAC) and R, written as a percent, is the risk of having a car accident. According the California Department of Motor Vehicles (DMV) it is illegal for any person to operate a vehicle with a: • BAC of 0.08% or higher, if the person is 21 years old or older. • BAC of 0.01% or higher, if the person is under 21 years old. What Blood Alcohol Concentration corresponds to a 17% risk of a car accident? What Blood Alcohol Concentration corresponds to a 7% risk of a car accident? Use the Blood Alcohol Concentration chart (on back) to determine the likelihood a 140 pound (lbs) female will be in an accident if she has had 5 drinks.What is the purpose of determining a measure of central tendancy?