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You are given the dollar value of a product in 2016 and the rate at which the value of the product is expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t = O represent 2010.) 2016 Value Rate $3,150 $450 increase per year Step 1 Recall that the slope of the line can be interpreted as a rate of change. In this case, the value increases as time passes and the rate of change is $450 per year. change in value (in dollars) rate of change = change in time (in years) 450 450 450 Therefore, the slope m of the linear function is m = 450 450 ep 2 We are to let t = 0 represent 2010. In 2016 the dollar value is given to be $3,150. Therefore, V = 3,150 when t = 6 his point on the graph of the linear function can be defined as (t,, v,) = (6 6 , 3,150). e the slope m = 450 and the point to express the relationship between variables V and t using the point-slope form. V- v, = m(t - t) t - 6)

You are given the dollar value of a product in 2016 and the rate at which the value of the product is expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t = O represent 2010.) 2016 Value Rate $3,150 $450 increase per year Step 1 Recall that the slope of the line can be interpreted as a rate of change. In this case, the value increases as time passes and the rate of change is $450 per year. change in value (in dollars) rate of change = change in time (in years) 450 450 450 Therefore, the slope m of the linear function is m = 450 450 ep 2 We are to let t = 0 represent 2010. In 2016 the dollar value is given to be $3,150. Therefore, V = 3,150 when t = 6 his point on the graph of the linear function can be defined as (t,, v,) = (6 6 , 3,150). e the slope m = 450 and the point to express the relationship between variables V and t using the point-slope form. V- v, = m(t - t) t - 6)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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You are given the dollar value of a product in 2016 and the rate at which the value of the product year t. (Let t = 0 represent 2010.) expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the 2016 Value Rate $3,150 $450 increase per year Step 1 Recall that the slope of the line can be interpreted as a rate of change. In this case, the value increases as time passes and the rate of change is $450 per year. change in value (in dollars) change in time (in years) 450 rate of change = %3D 1 = 450 450 Therefore, the slope m of the linear function is m = 450 450 Step 2 We are to let t = 0 represent 2010. In 2016 the dollar value is given to be $3,150. Therefore, V = 3,150 when t = 6 This point on the graph of the linear function can be defined as (t,, v,) = (6 6, 3,150). Step 3 Use the slope m = 450 and the point to express the relationship between variables V and t using the point-slope form. V - V, = m(t - t,) ( - 6) V-
Transcribed Image Text:You are given the dollar value of a product in 2016 and the rate at which the value of the product year t. (Let t = 0 represent 2010.) expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the 2016 Value Rate $3,150 $450 increase per year Step 1 Recall that the slope of the line can be interpreted as a rate of change. In this case, the value increases as time passes and the rate of change is $450 per year. change in value (in dollars) change in time (in years) 450 rate of change = %3D 1 = 450 450 Therefore, the slope m of the linear function is m = 450 450 Step 2 We are to let t = 0 represent 2010. In 2016 the dollar value is given to be $3,150. Therefore, V = 3,150 when t = 6 This point on the graph of the linear function can be defined as (t,, v,) = (6 6, 3,150). Step 3 Use the slope m = 450 and the point to express the relationship between variables V and t using the point-slope form. V - V, = m(t - t,) ( - 6) V-
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