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You are given an empty hash table of size 7 that uses open addressing (no chaining). Insert the following keys 15 17 8 23 35 into the table using each of the following approaches. If overflow occurs mark where it occurs and indicate the element that causes the overflow. a. h(x) = x % 7; linear probing b. h(x) = x % 7; quadratic probing 1 1 3 4 4 5 61 6. c. h(x)= x%7; double hashing with g(x) = x/7 +1 (using integer division) LO 3,

You are given an empty hash table of size 7 that uses open addressing (no chaining). Insert the following keys 15 17 8 23 35 into the table using each of the following approaches. If overflow occurs mark where it occurs and indicate the element that causes the overflow. a. h(x) = x % 7; linear probing b. h(x) = x % 7; quadratic probing 1 1 3 4 4 5 61 6. c. h(x)= x%7; double hashing with g(x) = x/7 +1 (using integer division) LO 3,

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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You are given an empty hash table of size 7 that uses open addressing (no chaining). Insert the following keys 15 17 8 23 35 into the table using each of the following approaches. If overflow occurs mark where it occurs and indicate the element that causes the overflow. a. h(x) = x % 7; linear probing b. h(x) = x % 7; quadratic probing 1 1 2 2 3 4 5 6 c. h(x)= x%7; double hashing with g(x) = x/7 +1 (using integer division) %3D CO
Transcribed Image Text:You are given an empty hash table of size 7 that uses open addressing (no chaining). Insert the following keys 15 17 8 23 35 into the table using each of the following approaches. If overflow occurs mark where it occurs and indicate the element that causes the overflow. a. h(x) = x % 7; linear probing b. h(x) = x % 7; quadratic probing 1 1 2 2 3 4 5 6 c. h(x)= x%7; double hashing with g(x) = x/7 +1 (using integer division) %3D CO
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