You are examining an ant with a magnifying lens that has focal length 5.00 cm. Part A If the image of the ant appears 24.0 cm from the lens, how far is the ant from the lens? ΜΕ ΑΣΦ -17.5 ? cm Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining
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- A converging lens with a focal length of 9.10 cm forms an image of a 5.60-mm-tall real object that is to the left of the lens. The image is 2.00 cm tall and erect. Where is the object located? Follow the sign rules. Express your answer with the appropriate units. 16.38 cm ? Submit Previous Answers Request Answer × Incorrect; Try Again; 4 attempts remaining Part B Where is the image located? Follow the sign rules. Express your answer with the appropriate units. 32.5 cm Submit Previous Answers Request Answer ? × Incorrect; Try Again; 4 attempts remaining Part C Is the image real or virtual? real virtual Submit Previous Answers Correct8)You are given a spherical mirror and wish to determine its properties. You place an object on its axis, 33.5 cm in front of it, and discover that the mirror creates a virtual image located 14.5 cm from the mirror. Determine the mirror's focal length / in centimeters. Calculate the mirror's radius of curvature C in centimeters. If it can be determined, is the mirror concave or convex? convex concave cannot be determined. cm cm
- Part A How far from a 51.0 mm focal-length lens must an object be placed if its image is to be magnified 2.60× and be real? do = = Submit Part B do = ΑΣΦ What if the image is to be virtual and magnified 2.60×? Submit Request Answer VE ΑΣΦ Request Answer ? ? mm mmA person looks at a gem using a converging lens with a focal length of 13.8 cm. The lens forms a virtual image 33.1 cm from the lens. Find the magnification. Describe the image. 1. real, upright, larger 2. real, inverted, larger 3. virtual, upright, larger 4. real, inverted, smaller 5. virtual, inverted, larger 6. real, upright, smaller 7. virtual, inverted, smaller 8. virtual, upright, smaller35.3
- A concave mirror produces a virtual image that is three times as tall as the object. Part A If the object is 12 cm in front of the mirror, what is the image distance? Express your answer using two significant figures. ΑΣφ ? di = cm Submit Request Answer Part B What is the focal length of this mirror? Express your answer using two significant figures. nν ΑΣφ ? cm Submit Request AnswerHelp.1. Determine the image distance and image height for a 5.0 cm tall object placed 30.0 cm from a concave mirror having a focal length of 15.0 cm. 2. Determine the image distance and image height for a 5.0 cm tall object placed 10 cm from a concave mirror having a focal length of 15 cm.
- Needs Complete typed solution with 100 % accuracy.A person looks at a gem using a converging lens with a focal length of 13.8 cm. The lens forms a virtual image 33.1 cm from the lens. Find the magnification. Describe the image. 1. real, upright, larger 2. real, inverted, larger 3. virtual, upright, larger 4. real, inverted, smaller 5. virtual, inverted, larger 6. real, upright, smaller 7. virtual, inverted, smaller 8. virtual, upright, smaller2. A convex lens with focal length f formed an image of the object is shown in the diagram below Object 10 cm 15 cm F, F2 Image F1 and F2 are the focus points of the lens. What is the focal length, fof the lens? А. 11.2 cm С. 12.2 ст В. 11.8 сm D. 14.5 cm