You are dealt one card from a 52-card deck. Find the probability that you are not dealt a ten.

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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**Card Probability Problem**

You are dealt one card from a 52-card deck. Find the probability that you are not dealt a ten.

---

The probability is [  ]. (Type an integer or a fraction. Simplify your answer.)

---

**Explanation:**

In a standard 52-card deck, there are four tens (one from each suit: hearts, diamonds, clubs, and spades). To find the probability of not being dealt a ten, calculate the number of ways to draw a card that is not a ten, which is 52 total cards minus 4 ten cards:

\[ 
52 - 4 = 48 \text{ non-ten cards}
\]

The probability of not getting a ten is then:

\[ 
\frac{48}{52} 
\]

Simplify the fraction:

\[ 
\frac{48 \div 4}{52 \div 4} = \frac{12}{13}
\]

Thus, the probability that you are not dealt a ten is \( \frac{12}{13} \).
Transcribed Image Text:**Card Probability Problem** You are dealt one card from a 52-card deck. Find the probability that you are not dealt a ten. --- The probability is [ ]. (Type an integer or a fraction. Simplify your answer.) --- **Explanation:** In a standard 52-card deck, there are four tens (one from each suit: hearts, diamonds, clubs, and spades). To find the probability of not being dealt a ten, calculate the number of ways to draw a card that is not a ten, which is 52 total cards minus 4 ten cards: \[ 52 - 4 = 48 \text{ non-ten cards} \] The probability of not getting a ten is then: \[ \frac{48}{52} \] Simplify the fraction: \[ \frac{48 \div 4}{52 \div 4} = \frac{12}{13} \] Thus, the probability that you are not dealt a ten is \( \frac{12}{13} \).
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