You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data. Population Population #2 Category # 1 A 10 144 в |47 18 The expected observations for this table would be Population Population #2 Category #1 A 40.082 113.918 v o B 16.918 48.082 (0 – E)? E The resulting are: Population Population #2 Category # 1 B What is the chi-square test-statistic for this data? x² = 102.8 What is the p-value for this test-statistic? p-value - 3.6485

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You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data.

| Category | Population #1 | Population #2 |
|----------|---------------|---------------|
| A        | 10            | 144           |
| B        | 47            | 18            |

The expected observations for this table would be:

| Category | Population #1 | Population #2 |
|----------|---------------|---------------|
| A        | 40.082        | 113.918       |
| B        | 16.918        | 48.082        |

The resulting \( \frac{{(O - E)^2}}{E} \) are:

| Category | Population #1 | Population #2 |
|----------|---------------|---------------|
| A        |               |               |
| B        |               |               |

What is the chi-square test statistic for this data?
\[
\chi^2 = 102.8
\]

What is the p-value for this test statistic?
p-value = 3.6485 (This value is incorrect as indicated by the red cross.)
Transcribed Image Text:You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data. | Category | Population #1 | Population #2 | |----------|---------------|---------------| | A | 10 | 144 | | B | 47 | 18 | The expected observations for this table would be: | Category | Population #1 | Population #2 | |----------|---------------|---------------| | A | 40.082 | 113.918 | | B | 16.918 | 48.082 | The resulting \( \frac{{(O - E)^2}}{E} \) are: | Category | Population #1 | Population #2 | |----------|---------------|---------------| | A | | | | B | | | What is the chi-square test statistic for this data? \[ \chi^2 = 102.8 \] What is the p-value for this test statistic? p-value = 3.6485 (This value is incorrect as indicated by the red cross.)
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