You are conducting a multinomial hypothesis test for the claim that the 4 categories occur with the following frequencies: Ho: (see below) pa = 0.4; pb = 0.1; pc = 0.2; pd=0.3 Category Observed Frequency A 49 B 11 C 30 D 33 What is the chi-square test-statistic for this data? χ2= ____ Report all answers accurate to three decimal places.

You are conducting a multinomial hypothesis test for the claim that the 4 categories occur with the following frequencies: Ho: (see below) pa = 0.4; pb = 0.1; pc = 0.2; pd=0.3 Category Observed Frequency A 49 B 11 C 30 D 33 What is the chi-square test-statistic for this data? χ2= ____ Report all answers accurate to three decimal places.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Category	Observed Frequency
A	49
B	11
C	30
D	33

Similar questions

A test of Ho:mu-3 vs Ha: mu not-3 resulted in a p-value of 0.13. We can predict that, using the same data set: • the 90% CI for mu • the 95% CI for mu [Select] . [Select] the 99% CI for mu [ Select] include 3 include 3 ✓include 3
Is there a significant relationship between subject’s IQ and pre-test scores?α =.05, two tailed, if the tests needs
0.97 is not the answer
2
Test for the claim that the following categories occur with the following frequencies: pA=0.3pA=0.3; pB=0.4pB=0.4; pC=0.2pC=0.2; pD=0.1pD=0.1Test at the 0.01 significance level. Complete the table. Round all answers to three decimal places. Category ObservedFrequency ExpectedFrequency Residual A 30 B 44 C 22 D 17 HoHo : pA=0.3pA=0.3; pB=0.4pB=0.4; pC=0.2pC=0.2; pD=0.1pD=0.1H1H1: at least one is different Original claim = Select an answer H₀ H₁ Enter the critical value, along with the significance level and degrees of freedom χ2χ2(αα,df) below the graph. (Graph is for illustration only. No need to shade.) X2Χ2(,) = (Round to three decimal places.) Test Statistic = (Round to three decimal places.)p-value=(Round to four decimal places.) Decision: Select an answer Fail to reject the null hypothesis Accept the alternative hypothesis Reject the null hypothesis Accept the null hypothesis Conclusion: Select an answer There is not…
A study was done to look at the relationship between number of lovers college students have had in their lifetimes and their GPAs. The results of the survey are shown below. Lovers 0 3 1 2 5 1 8 GPA 3.3 2.9 3.4 3.3 2.5 2.8 0.7 1. The p-value is: _____ (Round to four decimal places) 2. Use a level of significance of α=0.05 to state the conclusion of the hypothesis test in the context of the study (pick one). a. There is statistically significant evidence to conclude that there is a correlation between the number of lovers students have had in their lifetimes and their GPA. Thus, the regression line is useful. b. There is statistically significant evidence to conclude that a student who has had more lovers will have a lower GPA than a student who has had fewer lovers. c. There is statistically insignificant evidence to conclude that a student who has had more lovers will have a lower GPA than a student who has had fewer lovers. d. There is statistically insignificant…
Which of the following is not a cause of perfect multicollinearity? Select all that apply. One of the explanatory variables is equal to half of another explanatory variable for 100% of the observations in the sample. The correlation between two of the explanatory variables is 1.00. One of the explanatory variables is equal to half of another explanatory variable for 20% of the observations in the sample. A dummy variable for male is included at the same time as a dummy variable for non-male. One of the regressors is X and another regressor is X².
Table 2 summarized the result of the study on the relationship between anxiety and depression. Table 2: The summary of correlational analysis of depression and anxiety Correlations Depression Anxiety Pearson Correlation Depression .282 1.00 Anxiety Depression Anxiety .282 1.00 Sig (2-tailed) .003 .003 N Depression 112 112 Anxiety 112 112 A) State the null hypothesis for this stucy. B) You can reject Ho based on sig. value but the value of tis, a weak one. How can you explain that? C) How do you conclude this result? D) Based on this position, write the likely regression equation. E) Write down statistics representation of the correlationin APA format.
The value obtained for the test statistic, z, in a one-mean z-test is given. Also given is whether the test is two tailed, left tailed, or right tailed. Determine the P-value. Round to four decimal places, as needed. A left-tailed test: Z = -1.17
● Question 3 Only about 10% of all people can wiggle their ears. Is this percent different for millionaires? Of the 379 millionaires surveyed, 30 could wiggle their ears. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: 80 F3 Ho: ? Select an answer ✓ H₁: ? Select an answer ✓ c. The test statistic ? ✓ = d. The p-value = e. The p-value is ? ✓ a f. Based on this, we should [Select an answer the null hypothesis. g. Thus, the final conclusion is that ... Submit Question (please enter a decimal) O The data suggest the population proportion is not significantly different from 10% at a = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of millionaires who can wiggle their ears is different from 10%. $ (Please enter a decimal) O The data suggest the populaton proportion is significantly different from 10% at a = 0.01, so there is…
You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies: H.: PA = 0.4; PB 0.1; Pc = 0.3; PD %3D0.2 Complete the table. Report all answers accurate to three decimal places. Observed Expected Frequency Frequency Category A 50 24 28 34 What is the chi-square test-statistic for this data? (2 decimal places) x = %3| What is the P-Value? (3 decimal places) P-Value = For significance level alpha 0.1, What would be the conclusion of this hypothesis test? O Fail to reject the Null Hypothesis O Reject the Null Hypothesis
You are conducting a test of independence for the daim that there is an association between morning beverage and age. Juice Coffee Pop Tea 5 32 | 43 less than 25 19 18 25 or older 27 30 2 What is the chi-square test-statistic and the corresponding p-value for this data? [three decimal accuracy] p-value = [three decimal accuracy]