5:You are conducting a multinomial hypothesis test (a = 0.05) for the claim that all 5 categories areequally likely to be selected. Complete the table.CategoryABCF1DObservedFrequency252016E13Report all answers accurate to three decimal places. But retain unrounded numbers for futurecalculations.15What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places,and remember to use the unrounded Pearson residuals in your calculations.)x²2What are the degrees of freedom for this test?d.f.=O:What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value=-PRThe p-value is...O less than (or equal to) agreater than aExpectedFrequency111,668F2#3#80F3SA$MAY000886F4%5F5tv ♫ AMacBook AirAbF6&7F7PIZ*a▶11

Category Observed Frequency A 25 B 20 C 16 D 15 E 13

Answered: You are conducting a multinomial…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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#12). Please show how you solved the problem. Circle answers. Q2 is already provided.
The researchers used a 3-item 7-point scale to measure consumers' attitudes toward the company. The researchers most likely used the .as the indicator of the scale's quality/reliability. none of the above/below O coefficient alpha coefficient beta coefficient p
Please answer the question in the picture below to answer the question in the other picture
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.025 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? Click the icon to view the data. What are the hypotheses for this test? O A. Ho: At least one of the means is different from the others. H₁ H₁ H₂ H3 OB. Ho: H₁ H₁: H1 H₂ =H3 H₂ H3 OC. Ho: H₁ H₂ H3 H₁: At least one of the means is different from the others. O D. Ho: H₁ H₂ H3 H₁: H₁ H₂ =H3 Data Table Type A 6.2 6.2 6.5 7.4 7.1 6.1 6.9 7.3 6.9 6.7 Print C Type B 7.7 7.5 8.7 8.1 8.6 8.8 8.4 8.5 Type C 8.5 9.3 9.6 9.1 9.1 9.1 9.8 9.5 9.9 Done O X
please use one or two variable analysis to solve
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.05 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? Click the icon to view the data. What are the hypotheses for this test? OA. Ho: H₁ H₂ H3 H₁: H₁ H₂ H3 OB. Ho: H₁ H₂ =H3 H₁: At least one of the means is different from the others. O C. Ho: At least one of the means is different from the others. H₁: H₁=H₂ =H3 OD. Ho: H₁ H₂ H3 H₁: H1₁ H₂ H3 Determine the test statistic. F = (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to two decimal places as needed.) What is the conclusion of the test? the null hypothesis. Conclude that the type of vehicle Data Table C Type A 6.5 6.2 6.5 6.5 5.8 7.5 6.4 6.4 6.2 6.9…
Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 38 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 94 of the 111 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P1 #P2 Hy:P1 =P2 O B. Ho: P1 =P2 H1: P1 P2 H1: P1 #P2 Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? the null hypothesis. There sufficient evidence to support the claim that echinacea…
Data Table Type A 7.3 7.6 7.1 7.1 7.1 7.9 6.4. 6.9 7.5 7.2 Type B 8.7 8.2 8.3 7.7 8.8 8.2 8.7 7.1 Type С 8.5 8.3 9.3 9.2 9.3 9.5 8.8 8.7 8.5 - X
Consider the following data: −10, −10, 0, 3, −10, 3, 3 Step 1 of 3: Calculate the value of the sample Variance. Round your answer to one decimal place. Step 2 of 3: Calculate the value of the sample deviation. Round your answer to one decimal place. Step 3 of 3: Calculate the value of the range.
Complete the table. Observed Expected Frequency Frequency Residual Squared Category A 25 21 36 20 What is the chi-square test-statistic for this data? B
6 Given the following data: the first quartile Q1 =(17) and Inter-quartile Range (IQR = 117); Then the third quartile Q3 equals: (Write only the number) Answer:
Below are some descriptive statistics output by Minitab regarding the distribution of ages among passengers on the Titanic. Use this information to answer each part below. Variable N Minimum Median Q3 Range IQR _______________________________________________________________ Titanic Age 1046 .1667 28.00 39.00 79.8333 18.00 (a) What is the five-number summary of this variable? (b) Show mathematically that there will be at least one outlier in this variable.

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