You are conducting a Goodness of Fit Chi-Squared hypothesis test (a = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ((O-E)^2/E) A B C D Observed Expected Frequency Frequency 20 7 23 19 E 10 Round Expected values accurate to exactly 2 decimal places. Retain unrounded numbers for future calculations. Round the ((O-E)^2/E) values to 3 decimals. What is the chi-square test-statistic for this data? (Round answer to 3 decimal places, and remember to use the unrounded Pearson residuals in your calculations.) x²: What are the degrees of freedom for this test? d.f.= What is the p-value for this sample? (Round answer to 3 decimal places.) p-value= The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected. There is not sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected.
You are conducting a Goodness of Fit Chi-Squared hypothesis test (a = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ((O-E)^2/E) A B C D Observed Expected Frequency Frequency 20 7 23 19 E 10 Round Expected values accurate to exactly 2 decimal places. Retain unrounded numbers for future calculations. Round the ((O-E)^2/E) values to 3 decimals. What is the chi-square test-statistic for this data? (Round answer to 3 decimal places, and remember to use the unrounded Pearson residuals in your calculations.) x²: What are the degrees of freedom for this test? d.f.= What is the p-value for this sample? (Round answer to 3 decimal places.) p-value= The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected. There is not sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:**Chi-Squared Goodness of Fit Test:**
You are conducting a Goodness of Fit Chi-Squared hypothesis test (\(\alpha = 0.05\)) for the claim that all 5 categories are equally likely to be selected. Complete the table.
| Category | Observed Frequency | Expected Frequency | ((O-E)^2/E) |
|----------|--------------------|--------------------|-------------|
| A | 20 | | |
| B | 7 | | |
| C | 23 | | |
| D | 19 | | |
| E | 10 | | |
- **Instructions:**
- Round Expected values to exactly 2 decimal places. Retain unrounded numbers for future calculations.
- Round the ((O-E)^2/E) values to 3 decimal places.
- **Calculations Needed:**
- What is the chi-square test-statistic for this data? (Round answer to 3 decimal places, and remember to use the unrounded Pearson residuals in your calculations.)
- \(\chi^2 = \)
- What are the degrees of freedom for this test?
- d.f. =
- What is the p-value for this sample? (Round answer to 3 decimal places.)
- p-value =
- **Options for Conclusion:**
- The p-value is:
- ○ less than (or equal to) \(\alpha\)
- ○ greater than \(\alpha\)
- This test statistic leads to a decision to:
- ○ reject the null
- ○ fail to reject the null
- **Final Conclusion:**
- ○ There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected.
- ○ There is not sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected.
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