You are attempting to find the range of a cannon by shooting a cannonball at different angles. The cannon fires the ball with a velocity of 105 and you are firing across a level field. You try angles of 30°, 45°, and 60°.

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### Exercise: Projectile Motion of a Cannonball

You are attempting to find the range of a cannon by shooting a cannonball at different angles. The cannon fires the ball with a velocity of 105 m/s and you are firing across a level field. You try angles of 30°, 45°, and 60°.

#### Questions:

a. **How long is the cannonball in the air for each of the three attempts?**

b. **What is the maximum height for each of the cannonballs?**

c. **How far does each travel in the horizontal direction?**

### Explanation:

To solve these questions, you need to apply the principles of projectile motion. Each point below explains the different aspects that need to be calculated:

1. **Time of Flight (T):**
   - The total time the projectile remains in the air. 
   - Formula: \( T = \frac{2 \cdot V_0 \cdot \sin(\theta)}{g} \)
     - \( V_0 \): Initial velocity (105 m/s)
     - \( \theta \): Angle of projection (30°, 45°, 60°)
     - \( g \): Acceleration due to gravity (9.81 m/s²)

2. **Maximum Height (H):**
   - The peak vertical position reached by the projectile.
   - Formula: \( H = \frac{V_0^2 \cdot \sin^2(\theta)}{2 \cdot g} \)

3. **Horizontal Range (R):**
   - The total horizontal distance covered by the projectile.
   - Formula: \( R = \frac{V_0^2 \cdot \sin(2\theta)}{g} \)

#### Steps to solve:

1. **Calculate the Time of Flight for each angle (30°, 45°, 60°).**
2. **Determine the Maximum Height reached for each angle.**
3. **Compute the Horizontal Range for each angle.**

By solving these equations using the given data, you can derive the specific details for each angle of projection.
Transcribed Image Text:### Exercise: Projectile Motion of a Cannonball You are attempting to find the range of a cannon by shooting a cannonball at different angles. The cannon fires the ball with a velocity of 105 m/s and you are firing across a level field. You try angles of 30°, 45°, and 60°. #### Questions: a. **How long is the cannonball in the air for each of the three attempts?** b. **What is the maximum height for each of the cannonballs?** c. **How far does each travel in the horizontal direction?** ### Explanation: To solve these questions, you need to apply the principles of projectile motion. Each point below explains the different aspects that need to be calculated: 1. **Time of Flight (T):** - The total time the projectile remains in the air. - Formula: \( T = \frac{2 \cdot V_0 \cdot \sin(\theta)}{g} \) - \( V_0 \): Initial velocity (105 m/s) - \( \theta \): Angle of projection (30°, 45°, 60°) - \( g \): Acceleration due to gravity (9.81 m/s²) 2. **Maximum Height (H):** - The peak vertical position reached by the projectile. - Formula: \( H = \frac{V_0^2 \cdot \sin^2(\theta)}{2 \cdot g} \) 3. **Horizontal Range (R):** - The total horizontal distance covered by the projectile. - Formula: \( R = \frac{V_0^2 \cdot \sin(2\theta)}{g} \) #### Steps to solve: 1. **Calculate the Time of Flight for each angle (30°, 45°, 60°).** 2. **Determine the Maximum Height reached for each angle.** 3. **Compute the Horizontal Range for each angle.** By solving these equations using the given data, you can derive the specific details for each angle of projection.
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