1- You are assigned to evaluate the level of service for a section of a six-lane rural highwaythat stretches along a level terrain with shoulder width of eight ft and lane width oftwelve ft. The average annual daily traffic is fifty-five thousand vehicles per day with tenpercent trucks, five percent buses, and three percent recreational vehicles. The peak hourfactor is 0.80 and the directional split is fifty-fifty. The distance between consequentinterchanges is two miles. Calculate the level of service for this highway section andshow your calculation steps.

According to given data You are assigned to evaluate the level of service for a section of a six-lane rural highway that stretches along a level terrain with shoulder width of eight ft and lane width of twelve ft. The average annual daily traffic is fifty-five thousand vehicles per day with ten percent trucks, five percent buses, and three percent recreational vehicles. The peak hour factor is 0.80 and the directional split is fifty-fifty. The distance between consequent interchanges is two miles. To, Calculate the level of service for this highway section.To calculate the level of service for this highway section, we need to first determine the capacity of the highway. This can be calculated using the following formula: Capacity (vehicles per hour) = (Lane width (ft/lane) * Number of lanes * Peak hour factor) / (Shoulder width (ft/lane) + Lane width (ft/lane) + Length of a vehicle (ft/vehicle)) For this highway section, the capacity is calculated as follows: Capacity = (12 ft/lane * 6 lanes * 0.80) / (8 ft/lane + 12 ft/lane + 30 ft/vehicle) Capacity = (720 ft * 0.80) / (20 ft + 30 ft) Capacity = 576 vehicles/hour Next, we need to calculate the volume of traffic on the highway during the peak hour. This can be calculated using the following formula: Peak hour traffic volume = (Average annual daily traffic * Directional split * Peak hour factor) / Hours per day For this highway section, the peak hour traffic volume is calculated as follows: Peak hour traffic volume = (55,000 vehicles/day * 0.50 * 0.80) / 24 hours/day Peak hour traffic volume = 14,583.33 vehicles/hour Now that we have determined the capacity and peak hour traffic volume for this highway section, we can use the following formula to calculate the level of service: Level of service = (Peak hour traffic volume / Capacity) * 100% For this highway section, the level of service is calculated as follows: Level of service = (14,583.33 vehicles/hour / 576 vehicles/hour) * 100% Level of service = 25.33% Therefore, the level of service for this highway section is 25.33%.