Yes): particülár sölütion Let x(1) = 8(1), the Dirac's delta signal. Fill in the blanks in Table 1. Let x(t) = u(1), the unit-step signal. Fill in the blanks in Table 2. Now change the input and the state in the above dynamical system and let dy(t) -3y(t) – 28(t) + 3u(t) dt y(0-) = -5. Fill in the blanks in Table 3. Table 1
Yes): particülár sölütion Let x(1) = 8(1), the Dirac's delta signal. Fill in the blanks in Table 1. Let x(t) = u(1), the unit-step signal. Fill in the blanks in Table 2. Now change the input and the state in the above dynamical system and let dy(t) -3y(t) – 28(t) + 3u(t) dt y(0-) = -5. Fill in the blanks in Table 3. Table 1
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Question
D
![Consider the 1* -order continuous-time (CT) LTI dynamical system given
by the input-output differential equation
dy(t)
= -3y(t) + x(t)
dt
y(0-) =0.
Let the following symbols be used:
and the state
Y'm(0): impulse response
Yzın (t): zero-input response
Vzsa (1): zero-state response
Yea (1): complete response
Yesa () : unit-step response
Yus (1): homogeneous solution
Ys 1): particular solution
Let x(1) = 8(1), the Dirac's delta signal. Fill in the blanks in Table 1.
Let x(t) = u(t), the unit-step signal. Fill in the blanks in Table 2.
Now change the input and the state in the above dynamical system and
a)
b)
c)
let
dy(t)
= -3y(t) – 28(t) + 3u(t)
dt
y(0") = -5.
Fill in the blanks in Table 3.
Table 1
Yzz(1)
Yzz (1)
Ycr(1)
Table 2
Yese (1)
Yzz(1)
Table 3
Yz (1)
Ys (1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd608d163-84e5-41af-bce0-85f756b0bdeb%2F9b109ff6-3a2c-4bd5-8d4b-f55b48b23d28%2Fgryvsv_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the 1* -order continuous-time (CT) LTI dynamical system given
by the input-output differential equation
dy(t)
= -3y(t) + x(t)
dt
y(0-) =0.
Let the following symbols be used:
and the state
Y'm(0): impulse response
Yzın (t): zero-input response
Vzsa (1): zero-state response
Yea (1): complete response
Yesa () : unit-step response
Yus (1): homogeneous solution
Ys 1): particular solution
Let x(1) = 8(1), the Dirac's delta signal. Fill in the blanks in Table 1.
Let x(t) = u(t), the unit-step signal. Fill in the blanks in Table 2.
Now change the input and the state in the above dynamical system and
a)
b)
c)
let
dy(t)
= -3y(t) – 28(t) + 3u(t)
dt
y(0") = -5.
Fill in the blanks in Table 3.
Table 1
Yzz(1)
Yzz (1)
Ycr(1)
Table 2
Yese (1)
Yzz(1)
Table 3
Yz (1)
Ys (1)
![d)
Consider the input-output differential equation:
+Sy(t) = 3 de(1)
di
dr
di
Perform the necessary operations on the above equation in order to
put it into the appropriate form such that you can draw the first-
canonical form of the block-diagram model of this equation.
e)
Draw the first-canonical form of the block-diagram model.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd608d163-84e5-41af-bce0-85f756b0bdeb%2F9b109ff6-3a2c-4bd5-8d4b-f55b48b23d28%2Fhzto2v_processed.png&w=3840&q=75)
Transcribed Image Text:d)
Consider the input-output differential equation:
+Sy(t) = 3 de(1)
di
dr
di
Perform the necessary operations on the above equation in order to
put it into the appropriate form such that you can draw the first-
canonical form of the block-diagram model of this equation.
e)
Draw the first-canonical form of the block-diagram model.
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