Yes (b) The life spans of three randomly selected tires are 28,500 miles, 37,500 miles, and 33,000 miles. Using the empirical rule, find the percentile that corresponds to each life span. The life span 28,500 miles corresponds to a percentile of The life span 37,500 miles corresponds to a percentile of The life span 33,000 miles corresponds to a percentile of (Round to the nearest whole number as needed.)
Yes (b) The life spans of three randomly selected tires are 28,500 miles, 37,500 miles, and 33,000 miles. Using the empirical rule, find the percentile that corresponds to each life span. The life span 28,500 miles corresponds to a percentile of The life span 37,500 miles corresponds to a percentile of The life span 33,000 miles corresponds to a percentile of (Round to the nearest whole number as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A certain brand of automobile tire has a mean life span of 33,000 miles and a standard deviation of 2,250
miles. (Assume the life spans of the tires have a bell-shaped distribution.)
For the life span of 35,000 miles, z-score is 0.89.
(Round to the nearest hundredth as needed.)
For the life span of 36,000 miles, z-score is 1.33
(Round to the nearest hundredth as needed.)
For the life span of 31,000 miles, z-score is - 0.89.
(Round to the nearest hundredth as needed.)
According to the z-scores, would the life spans of any of these tires be considered unusual?
No
OYes
(b) The life spans of three randomly selected tires are 28,500 miles, 37,500 miles, and 33,000 miles. Using the
empirical rule, find the percentile that corresponds to each life span.
The life span 28,500 miles corresponds to a percentile of
The life span 37,500 miles corresponds to a percentile of
The life span 33,000 miles corresponds to a percentile of
(Round to the nearest whole number as needed.)
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