yA (\PF| = |PL| 2= 4py Focus: F(0, p) P(x, y) Vertex: (0, 0) Directrix: y = -p Lx, -p) Figure 12.46 QUICK CHECK 1 Verify that V + (y – p)² = y + p is equivalent to x? = 4py. <

Q: Evaluate fay'da + aªdy, where C is the rectangle with vertices (0,0), (1,0), (1,4), and (0,4)

A:

Q: Suppose XY has coordinates X( -2, 5) and Y(3, -9). What are the coordinates for the midpoint of XY?

A: To find the Midpoint of the line.

Q: Calculate the x- and y-interсepts of the graph:   y=3-3x^3   A)x - intercept (0,1), y -…

A: Draw the graph: For X-intercept, put y=0: X-intercept is 1. The point of x-intercept is (1, 0).

Q: Find the center, transverse axis, vertices, foci, and the asymptote of the y^2-x^2-4x+4y-1=0

A: Steps and explanations are as follows: In case of any doubt, please let me know. Thank you.

Q: What is the image of the point (4, -4) after the reflection over the line y = x-2?

A: we have to find the image under given line

Q: What is the reflection over the y-axis of (-7,8)

A: Given  Point : (-7,8)

Q: Find ∫C (2z + 9) / (z2 + 2z - 3) where C is the circle |z - 2| = 3.

A:

Q: Whatwillbethenewpositionofthegivenpoint(3,-5)afterreflectionacross the y-axis?

A: Reflection

Q: y=-2log_(2)(x+3)-1 Plot at least four points that fit on.

A:

Q: Find the y-intercept of the equation y = 7x - 2 y-intercept: Enter an n-tuple (more..] Submit…

A:

Q: =12 Sho

A: Straight line: The slope intercept form is y=mx+c Where m=slope. c is y-intercept.