yA (\PF| = |PL| 2= 4py Focus: F(0, p) P(x, y) Vertex: (0, 0) Directrix: y = -p Lx, -p) Figure 12.46 QUICK CHECK 1 Verify that V + (y – p)² = y + p is equivalent to x? = 4py. <

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A: Given function is y2=4x2x+5x-2  ....1

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A: Standard equation of circle (X-h)2+(y-k)2= r2   Center (h, k)  Radius = r

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A: To find the Midpoint of the line.

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A:

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A: Draw the graph: For X-intercept, put y=0: X-intercept is 1. The point of x-intercept is (1, 0).

Q: Find the center, transverse axis, vertices, foci, and the asymptote of the y^2-x^2-4x+4y-1=0

A: Steps and explanations are as follows: In case of any doubt, please let me know. Thank you.

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A: we have to find the image under given line

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A: Given  Point : (-7,8)

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Q: 4Standard form: 4.x +3y =9 Slope-intercept form:

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A: Reflection

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Q: y=-2log_(2)(x+3)-1 Plot at least four points that fit on.

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Q: =12 Sho

A: Straight line: The slope intercept form is y=mx+c Where m=slope. c is y-intercept.

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A: We are given : 2x2+3xy-4y2-3y+1=0 Plotting the graph, we have : This graph is a Hyperbola.

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Q: identify any symmetry here. y=x^(2)+3

A: Let y = f(x) = x^(2)+3, then  f(-x) = (-x)^(2)+3.     { Replace x  with (-x)}         = x^(2)+3…

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A: Here equation we have given is of a circle : x2+y2=4x.

Q: y = Vx²(x+ 1)

A: As per our company guidelines we are supposed to answer only first  1st question of multiple…