Homework Help is Here – Start Your Trial Now!
Math
Calculus
Y9gain 704 31.) Se Sine dx Chapter 8. Integration Techniques 8.2.31 Let u = e2x and du = er sin er dr Then du = 2r dx and v = - cos e. Then we have 2e e3a sin et d.x = p2x cos e" + 2 e20 cos e" dr. To compute the last integral, we let u = e and dv = the last integral is et cos e" dx. Then du = e dx and v = sin e". Then e2* cos e" dx = 2e" sin et -2 e" sin e" dx = 2e" sin e" + 2 cos e + C. Combining these results gives a final answer of 3x sin e" dx = e2 cos e +2e" sin e" + 2 cos e + C.

Y9gain 704 31.) Se Sine dx Chapter 8. Integration Techniques 8.2.31 Let u = e2x and du = er sin er dr Then du = 2r dx and v = - cos e. Then we have 2e e3a sin et d.x = p2x cos e" + 2 e20 cos e" dr. To compute the last integral, we let u = e and dv = the last integral is et cos e" dx. Then du = e dx and v = sin e". Then e2* cos e" dx = 2e" sin et -2 e" sin e" dx = 2e" sin e" + 2 cos e + C. Combining these results gives a final answer of 3x sin e" dx = e2 cos e +2e" sin e" + 2 cos e + C.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
See similar textbooks
icon
Related questions
Question

The question is for number 31, circled in orange. Why do we let u =e^2x instead of e^3x? What happened to the extra e^x?

31.) Se sine dx 704 xagain Chapter 8. Integration Techniques 8.2.31 Let u = e2 and dv et sin e" dx. Then du = 2e dx and v = - cos e9. Then we have | ešr sin e" da 3x 2x 2x -e COs e“ + 2 Cos e" dx. %3D To compute the last integral, we let u = the last integral is e and dv = e cos e" dx. Then du et dx and = sin e. Then 2x e cos e dx = 2e" sin e" - 2 e sin e" dx = 2e sin e" + 2 cos e" + C. Combining these results gives a final answer of e3* sin e" dx = e2 cos e" + 2e" sin e" + 2 cos e + C.
Transcribed Image Text:31.) Se sine dx 704 xagain Chapter 8. Integration Techniques 8.2.31 Let u = e2 and dv et sin e" dx. Then du = 2e dx and v = - cos e9. Then we have | ešr sin e" da 3x 2x 2x -e COs e“ + 2 Cos e" dx. %3D To compute the last integral, we let u = the last integral is e and dv = e cos e" dx. Then du et dx and = sin e. Then 2x e cos e dx = 2e" sin e" - 2 e sin e" dx = 2e sin e" + 2 cos e" + C. Combining these results gives a final answer of e3* sin e" dx = e2 cos e" + 2e" sin e" + 2 cos e + C.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS