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y=1; x=2; if (x>0) x=x+5+y; if (x==2) x=x-2+y; if (x=8) x=y=3;

y=1; x=2; if (x>0) x=x+5+y; if (x==2) x=x-2+y; if (x=8) x=y=3;

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question

In Java find the value of x , y after the statements are executed:

(statements are in picture)

The image contains the following code written in a programming language, likely resembling C or C++: ```c y = 1; x = 2; if (x > 0) x = x + 5 + y; if (x == 2) x = x - 2 + y; if (x == 8) x = y = 3; ``` ### Explanation: 1. **Initialization:** - `y` is assigned the value `1`. - `x` is assigned the value `2`. 2. **First Conditional Statement (`if (x > 0)`):** - Checks if `x` is greater than `0`. Since `x` is `2`, the condition is true. - Executes the statement `x = x + 5 + y;`. - Calculation: `x = 2 + 5 + 1`, resulting in `x = 8`. 3. **Second Conditional Statement (`if (x == 2)`):** - Checks if `x` equals `2`. Since `x` is `8`, the condition is false. - The corresponding block of code is not executed. 4. **Third Conditional Statement (`if (x == 8)`):** - Checks if `x` equals `8`. Since `x` is indeed `8`, the condition is true. - Executes the statement `x = y = 3;`. - Both `x` and `y` are assigned the value `3`. This sequence of code evaluates a set of conditions and performs arithmetic operations, demonstrating conditional execution and variable manipulation.
Transcribed Image Text:The image contains the following code written in a programming language, likely resembling C or C++: ```c y = 1; x = 2; if (x > 0) x = x + 5 + y; if (x == 2) x = x - 2 + y; if (x == 8) x = y = 3; ``` ### Explanation: 1. **Initialization:** - `y` is assigned the value `1`. - `x` is assigned the value `2`. 2. **First Conditional Statement (`if (x > 0)`):** - Checks if `x` is greater than `0`. Since `x` is `2`, the condition is true. - Executes the statement `x = x + 5 + y;`. - Calculation: `x = 2 + 5 + 1`, resulting in `x = 8`. 3. **Second Conditional Statement (`if (x == 2)`):** - Checks if `x` equals `2`. Since `x` is `8`, the condition is false. - The corresponding block of code is not executed. 4. **Third Conditional Statement (`if (x == 8)`):** - Checks if `x` equals `8`. Since `x` is indeed `8`, the condition is true. - Executes the statement `x = y = 3;`. - Both `x` and `y` are assigned the value `3`. This sequence of code evaluates a set of conditions and performs arithmetic operations, demonstrating conditional execution and variable manipulation.
Expert Solution
Explanation

Here we have x=2 and y=1.

Then, we have an if statement with condition x greater than 0, which is true, and hence the value of x gets updated to x+5+y.

Next, we have another if statement with condition x equals 2, which is false as x is updated to 8.

Next, we have another if statement with the condition x equals 8 which is true, and both x,y gets updated.

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