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:) y Y(t). *G:1,2: x(t)= 120 Sen (4t+π/2) y Y(t) = 60 Cos(2π/2 t + n) * G: 3;4: X(t)= 60 Sen (3t+π/3) y Y(t) = 12 Cos(4t+π/3) ♦ G: 5;6: x(t)= 120 Sen (60 πt+n/4) y Y(t)= 120 Cos(15t+n/4) ⚫G: 7;8: X(t)= 60 Sen (3πt+π/2) y Y(t) = 15 Cos(3πt+n/2) • G: 9;10: x(t)= 60 Sen (t+/2) y Y(t) = Cos(4t+0) > G: 11 x(t)= 60 Sen (3t+π/2) y Y(t)= 5 Cos(4t+2n)

:) y Y(t). *G:1,2: x(t)= 120 Sen (4t+π/2) y Y(t) = 60 Cos(2π/2 t + n) * G: 3;4: X(t)= 60 Sen (3t+π/3) y Y(t) = 12 Cos(4t+π/3) ♦ G: 5;6: x(t)= 120 Sen (60 πt+n/4) y Y(t)= 120 Cos(15t+n/4) ⚫G: 7;8: X(t)= 60 Sen (3πt+π/2) y Y(t) = 15 Cos(3πt+n/2) • G: 9;10: x(t)= 60 Sen (t+/2) y Y(t) = Cos(4t+0) > G: 11 x(t)= 60 Sen (3t+π/2) y Y(t)= 5 Cos(4t+2n)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Telecommunications: NO USE CHATGPT 1.- Given the signs X(t) and Y(t). -Determine the signal period: 2 x(t) + 3 y(t) if: -Determine angular frequency of X(t), its period and its frequency: - Find the power of y(t), if y(t) is a voltage signal: Indicate the units of Value obtained -Represent the signal y(t) in a factorial way (NOTE: justify your answer, if you do not justify the answer will not be qualified).
:) y Y(t). *G:1,2: x(t)= 120 Sen (4t+π/2) y Y(t) = 60 Cos(2π/2 t + n) * G: 3;4: X(t)= 60 Sen (3t+π/3) y Y(t) = 12 Cos(4t+π/3) ♦ G: 5;6: x(t)= 120 Sen (60 πt+n/4) y Y(t)= 120 Cos(15t+n/4) ⚫G: 7;8: X(t)= 60 Sen (3πt+π/2) y Y(t) = 15 Cos(3πt+n/2) • G: 9;10: x(t)= 60 Sen (t+/2) y Y(t) = Cos(4t+0) > G: 11 x(t)= 60 Sen (3t+π/2) y Y(t)= 5 Cos(4t+2n)
Transcribed Image Text::) y Y(t). *G:1,2: x(t)= 120 Sen (4t+π/2) y Y(t) = 60 Cos(2π/2 t + n) * G: 3;4: X(t)= 60 Sen (3t+π/3) y Y(t) = 12 Cos(4t+π/3) ♦ G: 5;6: x(t)= 120 Sen (60 πt+n/4) y Y(t)= 120 Cos(15t+n/4) ⚫G: 7;8: X(t)= 60 Sen (3πt+π/2) y Y(t) = 15 Cos(3πt+n/2) • G: 9;10: x(t)= 60 Sen (t+/2) y Y(t) = Cos(4t+0) > G: 11 x(t)= 60 Sen (3t+π/2) y Y(t)= 5 Cos(4t+2n)
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