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y" − (x + 1)y' — y = 0 a. do y = a₁ [1 + x² + ²x¹ + ² xº + ... ] + α₁ [x + ½ x³ + 1⁄2x5 + ²/3; +=x' + 1 1 b. y = ao [1 + ·x² + x³ + x² + -·|· + ... a1 x+ x += x² + + c. y = a₁ [1 + x² + x³ + ²x^² + ... C. + + d. y = ... · ao √x + ²/² x ² + ₁ x³ + [1⁄x² + ½ x³ + ¼ x4 + ···] ao ªo [⁄/ x² + ² x³ + ² x4 + ··· ] + a₁ + ·1

y" − (x + 1)y' — y = 0 a. do y = a₁ [1 + x² + ²x¹ + ² xº + ... ] + α₁ [x + ½ x³ + 1⁄2x5 + ²/3; +=x' + 1 1 b. y = ao [1 + ·x² + x³ + x² + -·|· + ... a1 x+ x += x² + + c. y = a₁ [1 + x² + x³ + ²x^² + ... C. + + d. y = ... · ao √x + ²/² x ² + ₁ x³ + [1⁄x² + ½ x³ + ¼ x4 + ···] ao ªo [⁄/ x² + ² x³ + ² x4 + ··· ] + a₁ + ·1

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Power Series
Find the Power series solution for the given differential equations centered at 0
y" − (x + 1)y' — y = 0 a. do y = a₁ [1 + x² + ²x¹ + ² xº + ... ] + α₁ [x + ½ x³ + 1⁄2x5 + ²/3; +=x' + 1 1 b. y = ao [1 + ·x² + x³ + x² + -·|· + ... a1 x+ x += x² + + c. y = a₁ [1 + x² + x³ + ²x^² + ... C. + + d. y = ... · ao √x + ²/² x ² + ₁ x³ + [1⁄x² + ½ x³ + ¼ x4 + ···] ao ªo [⁄/ x² + ² x³ + ² x4 + ··· ] + a₁ + ·1
Transcribed Image Text:y" − (x + 1)y' — y = 0 a. do y = a₁ [1 + x² + ²x¹ + ² xº + ... ] + α₁ [x + ½ x³ + 1⁄2x5 + ²/3; +=x' + 1 1 b. y = ao [1 + ·x² + x³ + x² + -·|· + ... a1 x+ x += x² + + c. y = a₁ [1 + x² + x³ + ²x^² + ... C. + + d. y = ... · ao √x + ²/² x ² + ₁ x³ + [1⁄x² + ½ x³ + ¼ x4 + ···] ao ªo [⁄/ x² + ² x³ + ² x4 + ··· ] + a₁ + ·1
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