y? (x² + 1) x(y2 + 1) 4. Solve the IVP y = y(-1) = 3. You may leave your answer in implicit form.

Q: y1 =  8x,  y2 =  (6x -  1), and y1 exceeds y2 by 2.

A:

Q: ve for y esec(4y²-6y+14) = 3x + 1

A: We have to solve for y of the given equation

Q: Enter the number that belongs in the green box as you solve for y. [(y)/(5)+7]=[3],[-7-[?]]

A: Let us solve above problem

Q: Find the point on the line 6x + y = 8 that is closest to the point (−4, 1).

A: to find:- point Q(x,y).

Q: Find the point 2/3 of the way from (−6, 6, 5) to (−8, −8, −5). P=(??,?)

A: Here we have to find the point 2/3 of the way from (-6,6,5) to (-8,-8,-5).

Q: -3y-9(2y+1)=7-5(6-y) solve for y

A:

Q: Is (6,7) a solution for y=11x+8?

A: Given:

Q: Y=2x+3 y-x=1

A: Given, y = 2x + 3           .....................(1) y - x = 1…