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y" (t) + ky' (t) + y(t) = 8(t – 1), y(0) = 0, y'(0) = 0 %3D

y" (t) + ky' (t) + y(t) = 8(t – 1), y(0) = 0, y'(0) = 0 %3D

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 9T
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Which of the following is the solution of the Differential Equation with initial values?
(img8)


Select one:
(img9)

%3D y" (t) + ky' (t) + y(t) = 8(t – 1), y(0) = 0, y'(0) = 0
Transcribed Image Text:%3D y" (t) + ky' (t) + y(t) = 8(t – 1), y(0) = 0, y'(0) = 0
H(t – 1) V4 - k2 (ck/2 sin(t/4 – k²)) a. y(t) = 1 b. y(t) : ek(t-1) sin((t – 1) /k? + 4 %3D k2 + 4 c. y(t) = k (e*#/? sin (tv/4 – )) ekt/2 2H(t – 1) t – 1 d. y(t) e k(t-1)/2 sin /4 – k2 %3D V4 - k2
Transcribed Image Text:H(t – 1) V4 - k2 (ck/2 sin(t/4 – k²)) a. y(t) = 1 b. y(t) : ek(t-1) sin((t – 1) /k? + 4 %3D k2 + 4 c. y(t) = k (e*#/? sin (tv/4 – )) ekt/2 2H(t – 1) t – 1 d. y(t) e k(t-1)/2 sin /4 – k2 %3D V4 - k2
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