y S C
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
A cross section in the shape of a circular arc
of constant thickness is shown in the figure. Derive
the following formula for the distance e from the center
of the arc to the shear center S:
e = [2r(sin(β)-cos(β))] / [ β-sin(β)cos(β) ]
in which β is in radians. Also, plot a graph showing
how the distance e varies as β varies from 0 to π.
Transcribed Image Text:y
S
C
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