**Transcription for Educational Website:**---**Variables and Definitions:**- \( \gamma \) is the specific weight of the liquid- \( h \) is the change in elevation within a liquid- \( \Delta P \) represents a change in pressure**Problem Statement:**Prove that:\[ \Delta P = \gamma h \]---**Explanation:**This formula represents a fundamental principle in fluid statics, indicating how the pressure in a fluid changes with a change in height, given the fluid's specific weight.

We know Pressure=ForceAreaUsing Newtons lawF=maWe knowDensity=massVolumem=ρ×Vso,F=maF=ρ×Va

Answered: y is the specific weight of liquid, h…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Select the most appropriate answer. O Bemoulli eg was derived by applying Newton's 2nd law to a particle and then integrating along a streamline: while Energy eg was derived using the 1st law of thermodynamics & consequently the Reynolds transoort theorem. Energy eg includes both mechanical.and thermal eneray, while Bernouli eg involves only.mechanical eneray. Bernoulli eg is applied by selecting two.points (can be anywhere) on a streamline (irrotational flow) and then equating terms at those points, while Energy eg is applied by selecting an inlet & on outlet sections and then equating terms at those sections. Energy eg applies to steady. incompressible. viscous flow with additional energies through the pumR. turbine, and heat engines: while Bemoulli eg applies to steady. incompressible, and inviscid flow (h = 0, a = 1). Under special circumstances, Bernoulli eg converts into Energy eg if pump or turbine added along the streamline Bernouli eg was derived by applying Newtan's 2nd law…
B P A y W Find the Vertical Position of the Centroid marked as y on the Diagram using the transform section method, transforming all your material to Material A. Your Answer should be in mm to 1 decimal place. J-22.0 mm, P=76.8 mm, W-187.2mm, Young's Modulus of Material A = 64.5 GPa, Yield Stress of Material A = 145.9 MPa, Young's Modulus of Material B = 94.4 GPa, Yield Stress of Material B = 272.9 MPa.
For fluid undergoing circular motion, the centripetal force is provided by a pressure difference. Consider a fluid element (density p) at radial distance r, which has thickness dr in the radial direction and surface area dA normal to the radial direction. The pressure difference gives rise to a force on the fluid element equal to (p(r + dr) – p(r))dA. (i) Equating the pressure difference to the centripetal force, find an expression for the radial pressure gradient in terms of p, r, and fluid velocity v. (ii) A fluid is undergoing body rotation in the r-0 plane (cylindrical polar co-ordinates). By considering the gravitational pressure head, show that the shape of a free surface z(r) is parabolic. (iii) Find and sketch a similar expression for the free surface of a fluid vortex produced by a rotating cylindrical spindle (i.e. a solid cylindrical rod) of radius Ro.

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y is the specific weight of liquid, h is the change in the elevation in a liquid Ap a change in pressure Prove that AP = yh %3D