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y for y = 1, ..., 5 be the pmf of Y? 56 (d) Could p(y) - No because ply) = 1 Need Help? Read It 332 P ENG 2/27/202

y for y = 1, ..., 5 be the pmf of Y? 56 (d) Could p(y) - No because ply) = 1 Need Help? Read It 332 P ENG 2/27/202

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature of the project) in applying for a building permit. Let Y = the number of forms required of the next applicant. The probability that y forms are required is known to be proportional to y-that is, P(Y) = ky for y = 1, ..., 5. (Enter your answers as fractions.) (a) What is the value of k? (Hint: p(y) = 1] y- 1 k = 1/15 (b) What is the probability that at most three forms are reguired? 2/5 (c) What is the probability that between two and four forms (inclusive) are required? 0.60 (d) Could p(y) = Y for y = 1, ..., 5 be the pmf of Y? 56 No because p(y) = -1 y= 1 Need Help? Read It 3:32 PM ENG P 2/27/2022 DELL Esc F1 F2 F3 F4 F5 F6 F7 F8 F9 F10 F11 F12 PrtScr Insert Delete 40 @ %23 %24 & + 2 3 4 6 8 9. Backspace %3D Tab W U Caps Lock D F G K Enter mift C B Shift Fn Alt t PgUp Alt Ctrl Home PgDn End Inspiron 14 5000 2-in-1 Acove Purs Tovens
Transcribed Image Text:A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature of the project) in applying for a building permit. Let Y = the number of forms required of the next applicant. The probability that y forms are required is known to be proportional to y-that is, P(Y) = ky for y = 1, ..., 5. (Enter your answers as fractions.) (a) What is the value of k? (Hint: p(y) = 1] y- 1 k = 1/15 (b) What is the probability that at most three forms are reguired? 2/5 (c) What is the probability that between two and four forms (inclusive) are required? 0.60 (d) Could p(y) = Y for y = 1, ..., 5 be the pmf of Y? 56 No because p(y) = -1 y= 1 Need Help? Read It 3:32 PM ENG P 2/27/2022 DELL Esc F1 F2 F3 F4 F5 F6 F7 F8 F9 F10 F11 F12 PrtScr Insert Delete 40 @ %23 %24 & + 2 3 4 6 8 9. Backspace %3D Tab W U Caps Lock D F G K Enter mift C B Shift Fn Alt t PgUp Alt Ctrl Home PgDn End Inspiron 14 5000 2-in-1 Acove Purs Tovens
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