y = f (t) is the solution of the following diff. equation. y"+ y = tan x → homogenous solutions are y, and y, y(t)=(homogen part solution)+(nonhomogenous part solution) nonhomogenous part solution = u,y1 +U2Y2 in order to find u, and u, ,if we use the variation of parameters method, we write two equations: 1→u'y; +u, y, = 0 2 → u'v + u, y = .?... .... what is written instead of '...?...' in equation (2)?
y = f (t) is the solution of the following diff. equation. y"+ y = tan x → homogenous solutions are y, and y, y(t)=(homogen part solution)+(nonhomogenous part solution) nonhomogenous part solution = u,y1 +U2Y2 in order to find u, and u, ,if we use the variation of parameters method, we write two equations: 1→u'y; +u, y, = 0 2 → u'v + u, y = .?... .... what is written instead of '...?...' in equation (2)?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![y = f(t) is the solution of the following diff. equation.
y" + y = tan x → homogenous solutions are y, and y,
y(t)=(homogen part solution)+(nonhomogenous part solution)
nonhomogenous part solution = U,y1 +U½Y2
in order to find u, and u, if we use the variation of parameters method,
we write two equations:
1→ u'y, + u, y, =
2 → ujvi + u, y, :
what is written instead of '...?...' in equation (2)?
.?..
....](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e48c391-3251-407d-9480-d4f5ad826971%2Fe93caf0e-e823-4dd2-a712-2902a5b2cb43%2F2clythc_processed.png&w=3840&q=75)
Transcribed Image Text:y = f(t) is the solution of the following diff. equation.
y" + y = tan x → homogenous solutions are y, and y,
y(t)=(homogen part solution)+(nonhomogenous part solution)
nonhomogenous part solution = U,y1 +U½Y2
in order to find u, and u, if we use the variation of parameters method,
we write two equations:
1→ u'y, + u, y, =
2 → ujvi + u, y, :
what is written instead of '...?...' in equation (2)?
.?..
....
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