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y dy (13.) x = dx دول = 2xe* - y + 6x² 14. (3x²y + e') dx + (x³ + xe - 2y) dy = 0 3 3 (15.) (1+y)dx + (1 - ² + x)dy-0 = y 16. (e' + 2xy cosh x)y' + xy2 sinh x + y² cosh x = 0 1 17. (x²y³ - dx 1 + 9x²) dy given by + x³y² = 0

y dy (13.) x = dx دول = 2xe* - y + 6x² 14. (3x²y + e') dx + (x³ + xe - 2y) dy = 0 3 3 (15.) (1+y)dx + (1 - ² + x)dy-0 = y 16. (e' + 2xy cosh x)y' + xy2 sinh x + y² cosh x = 0 1 17. (x²y³ - dx 1 + 9x²) dy given by + x³y² = 0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Can someone please help me answer number 17
Answers In Problems 1-24 determine whether the given equation is exact. If it is exact, solve. 1. (2x - 1)dx + (3y + 7)dy = 0 3. (5x + 4y)dx + (4x − 8y³) dy = 0 - 4. (siny - y sin x) dx + (cos x + x cos y - y)dy = 0 5. (2y²x - 3) dx + (2yx² + 4)dy = 0 6. 2y (2y- 8. -- + cos3x X 7. (x+y)(x - y) dx + x(x - 2y) dy = 0 (1 + 1 ²)dx = (1 - In x) dy 12. 1 + ln x + 9. (y³ - y²sinx - x) dx + (3xy² + 2y cosx)dy = 0 10. (x³ + y³) dx + 3xy²dy = 0 2x (11.) myx+y)dy - 0 + ( + x In y dy = dy = 0 dx - 2. (2x + y) dx - (x + 6y)dy = 0 dy + - 4x³ + 3y sin 3x = 0 dx x² dy (13.) x = dx e = 2xe* - y + 6x² + x³y² = 0 Symbol is the 14. (3x²y + e') dx + (x³ + xe - 2y) dy = 0 3 3 ® (1 - ² + y ) dx + (1 - ² + x)dy-0 (15.) = X y 16. (e) + 2xy cosh x)y' + xy² sinh x + y² cosh x = 0 1 dx 17.x²y³ 1 + 9x²) dy
Transcribed Image Text:Answers In Problems 1-24 determine whether the given equation is exact. If it is exact, solve. 1. (2x - 1)dx + (3y + 7)dy = 0 3. (5x + 4y)dx + (4x − 8y³) dy = 0 - 4. (siny - y sin x) dx + (cos x + x cos y - y)dy = 0 5. (2y²x - 3) dx + (2yx² + 4)dy = 0 6. 2y (2y- 8. -- + cos3x X 7. (x+y)(x - y) dx + x(x - 2y) dy = 0 (1 + 1 ²)dx = (1 - In x) dy 12. 1 + ln x + 9. (y³ - y²sinx - x) dx + (3xy² + 2y cosx)dy = 0 10. (x³ + y³) dx + 3xy²dy = 0 2x (11.) myx+y)dy - 0 + ( + x In y dy = dy = 0 dx - 2. (2x + y) dx - (x + 6y)dy = 0 dy + - 4x³ + 3y sin 3x = 0 dx x² dy (13.) x = dx e = 2xe* - y + 6x² + x³y² = 0 Symbol is the 14. (3x²y + e') dx + (x³ + xe - 2y) dy = 0 3 3 ® (1 - ² + y ) dx + (1 - ² + x)dy-0 (15.) = X y 16. (e) + 2xy cosh x)y' + xy² sinh x + y² cosh x = 0 1 dx 17.x²y³ 1 + 9x²) dy
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\left(x^2y^3-\frac{1}{1+9x^2}\right)\:\frac{dx}{dy}+x^3y^2=0

\left(x^2y^3-\frac{1}{1+9x^2}\right)dx+\left(x^3y^2\right)dy=0

compare this equation with 

(M)dx+(N)dy=0

so here we have

M=x^2y^3-\frac{1}{1+9x^2}, \:\:\: N=x^3y^2

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