y (az + √2) sin (ay²) dy + (az − √√2) dz = 0 4√2 ln az + √2 = C 4√2 In az + √2 = C 4√2ln az + √2 = C Solvex (az + √2) dx O a. ay2 + a cos (ay²) + 2az O b. ax² + acos (ay²) + 2az 0 с. ах2 a cos (ay²) + 2az -

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve through separable differential equation

-
Solvex (az + √2) dx − y (az + √2) sin (ay²) dy + (az
O a. ay2 + acos (ay²) + 2az
O b. ax² + acos (ay²) + 2az
0 с. ах2 - a cos (ay2) + 2az
-
4√2 In|az + √2 = C
4√2 ln az + √√2 = C
4√2ln az + √2 = C
√2) dz = 0
Transcribed Image Text:- Solvex (az + √2) dx − y (az + √2) sin (ay²) dy + (az O a. ay2 + acos (ay²) + 2az O b. ax² + acos (ay²) + 2az 0 с. ах2 - a cos (ay2) + 2az - 4√2 In|az + √2 = C 4√2 ln az + √√2 = C 4√2ln az + √2 = C √2) dz = 0
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