y" + 6y +9y (2t + t^)e-³t = then the characteristic equation that can be derived from the PD above is r² + 6r + 9 = 0 => r₁ = -3 dan r₂ = -3, meaning that r is a twin root. Which is the homogeneous solution (take the right side of the equation equal to 0) of the PD: O a. y(t) = ce-3t O b. O c. y(t) = ce-³t+ C₂te-³t y(t) = c₁e¹+ C₂te-³t O d. y(t) = cte-³t

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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How to answer attached differential equation with detail explanations ?

When given a Differential Equation as follows
y" + 6y +9y (2t+t²¹)e-³t
then the characteristic equation that can be derived
from the PD above is r² + 6r+ 9 = 0 => r₁ = -3 dan r₂ = -3, meaning
that r is a twin root.
=
Which is the homogeneous solution (take the right
side of the equation equal to 0) of the PD:
a. y(t) = ce-3t
O b.
y(t) = ce-3t+c₂te-³t
O c.
O d. y(t) = cte-³t
y(t) = cet+ C₂te-³t
Transcribed Image Text:When given a Differential Equation as follows y" + 6y +9y (2t+t²¹)e-³t then the characteristic equation that can be derived from the PD above is r² + 6r+ 9 = 0 => r₁ = -3 dan r₂ = -3, meaning that r is a twin root. = Which is the homogeneous solution (take the right side of the equation equal to 0) of the PD: a. y(t) = ce-3t O b. y(t) = ce-3t+c₂te-³t O c. O d. y(t) = cte-³t y(t) = cet+ C₂te-³t
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