y" - 5y' = x - 2, when x = 0, y = 0, y' = 2

Q: 1. (2x-y) dx +(4x+y-6)dy=0

A: “Since you have posted multiple questions, we will provide the solution only to the first question…

Q: Perform the following equation using PEMDAS shown in the image. Write your answer together with its…

A: Disclaimer: Since you have asked multiple questions, we will solve the first question for you. If…

Q: e' 12.22. * – 4x + 3x: 1+e'

A:

Q: y" +y' – 2y = 4e* – 2x

A: We have the given differential equation is y''+y'-2y=4e-x-2x2     …..(1) The auxiliary equation for…

Q: cos y dx - 2x sin y dy = 0

A:

Q: y(2x? - xy + 1) dx + (x - y) dy = 0, ANS. y(2x – y) = c exp (-x?).

A: Given differential equation is y(2x2-xy+1)dx+(x-y)dy=0

Q: ye2xdx ye2x. (4 + e2x)dy

A: The given equation is ye2xdx=4+e2xdy The given differential equation can be solved by converting it…

Q: e 6. x" +2x'+x =- 1+12°

A: Answer

Q: ¯'x' = 47] [²] + [²³=_=+ e 4 t ] 3 — e4t- -te4t 2 L6 3.

A:

Q: Consider the differential equation: 1. y"-y%D What is the general solution? y= [a + In(1 +te *)]e* +…

A:

Q: Мaximize z = 3x1 + 5x2 subject to: 4x] + х, < 25 2х, + 3x, < 15 with х, 2 0, х, 2 0.

A: To Maximise  z= 3x1+5x2subjected to : 4x1+x2 ≤25                         2x1+3x2≤15 with…

Q: sin?x dx - tan°ydy

A: Using variable separable method,

Q: Find the General Solution of (D² + 5DD' + 6D²)Z = 10 cos(x – y)

A: Given partial differential equation is D2+5DD'+6D'2Z=10cosx−y. We have to find the general solution…

Q: y" - 2y' = e³t+cost +6

A:

Q: eメ B-4D+

A:

Q: Solve each of the following: (x − y − 2)dx + (3x + y - 10)dx = 0

A:

Q: 4. (-9) h()== In dx

A:

Q: .2 x cos?y dx + tan y dy = 0

A: The given differential equation is  x cos2y dx+tan y dy=0 Solving the the given differential…

Q: Students were given different drug treatments before revising for their exams. Some were given a…

A:

Q: Determine the solutions of: y^n  + 4y  = 0 y(-π) = y(π), y´(-π) = y´(π)

A:

Q: Find the general solution using Methods of Undetermined Coefficient and Variation of Parameters.…

A:

Q: Show that xp-yq=z and x^2p+q=xz are compatible and solve them

A: Given   :   xp-yq =z and  x2p+q =xz To find : Solution of Differential equation

Q: 5X1 + 4X2 + X3 = 3.4 10X1 + 9X2 + 4X3 = 8.8 10X1 + 13X2 + 15X3 = 19.2 %3!

A:

Q: 5sin 20 – 16sin0+3=0

A:

Q: dr r2 ;r(1) = 2 dø

A: