Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Find y'
![The equation shown in the image is:
\[ y = \frac{1}{2} \tan^{-1}\left(\sqrt[3]{x}\right) \]
This is a mathematical expression representing a function \( y \) in terms of \( x \). Here, \( \tan^{-1} \) denotes the inverse tangent function (also known as arctan), and \( \sqrt[3]{x} \) represents the cube root of \( x \). The entire expression for the arctan is multiplied by \( \frac{1}{2} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdec6af38-3348-4b7d-979b-f3d453210b87%2F6276fbbc-742e-441d-a0a1-e68e47ee82a8%2Fr09t4h_processed.png&w=3840&q=75)
Transcribed Image Text:The equation shown in the image is:
\[ y = \frac{1}{2} \tan^{-1}\left(\sqrt[3]{x}\right) \]
This is a mathematical expression representing a function \( y \) in terms of \( x \). Here, \( \tan^{-1} \) denotes the inverse tangent function (also known as arctan), and \( \sqrt[3]{x} \) represents the cube root of \( x \). The entire expression for the arctan is multiplied by \( \frac{1}{2} \).
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