(y-5) (3,7) 5 units away say find all the valub of y. distance formula use D= √(x²₂³x)² + (Y₂= y)²

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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### Finding Distance Using the Distance Formula

In this educational example, the task is to find all the values of \( y \) such that the point \( (y-5, 3) \) is 5 units away from the point \( (3, 7) \). 

#### Problem Description:
Find all the values of \( y \). 
> **Hint:** Use the distance formula.

#### Formula Provided:

The distance formula used in this context is:

\[ D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

where \( (x_1, y_1) \) and \( (x_2, y_2) \) are the coordinates of the two points, and \( D \) is the distance between them.

#### Steps:

1. Identify the coordinates of the points:
   - Point 1 (\( x_1, y_1 \)) = (3, 7)
   - Point 2 (\( x, y \)) = (x, y-5)
   
2. Substitute the values into the distance formula, where \( D = 5 \):

   \[
   5 = \sqrt{(3 - x)^2 + (7 - (y-5))^2}
   \]

3. Simplify the equation:

   \[
   5 = \sqrt{(3 - 3)^2 + (7 - y + 5)^2}
   \]

   \[
   5 = \sqrt{0 + (12 - y)^2}
   \]

4. To find the values of \( y \), we need to solve:

   \[
   5 = |12 - y|
   \]

This will result in two cases:

   1. \( 5 = 12 - y \)
   2. \( 5 = y - 12 \)

5. Solving these two cases will yield the possible values of \( y \).

Note: While this guide explains the setup and initial process, complete solving to find all \( y \) is left as an exercise for the student.

#### Additional Example:
### Evaluation of Quadratic Expressions

1. **Expression Given:**

   \[
   3(2)^2 - 4(2)
   \]

   Simplify Step-By-Step:
   \[
   3(
Transcribed Image Text:### Finding Distance Using the Distance Formula In this educational example, the task is to find all the values of \( y \) such that the point \( (y-5, 3) \) is 5 units away from the point \( (3, 7) \). #### Problem Description: Find all the values of \( y \). > **Hint:** Use the distance formula. #### Formula Provided: The distance formula used in this context is: \[ D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] where \( (x_1, y_1) \) and \( (x_2, y_2) \) are the coordinates of the two points, and \( D \) is the distance between them. #### Steps: 1. Identify the coordinates of the points: - Point 1 (\( x_1, y_1 \)) = (3, 7) - Point 2 (\( x, y \)) = (x, y-5) 2. Substitute the values into the distance formula, where \( D = 5 \): \[ 5 = \sqrt{(3 - x)^2 + (7 - (y-5))^2} \] 3. Simplify the equation: \[ 5 = \sqrt{(3 - 3)^2 + (7 - y + 5)^2} \] \[ 5 = \sqrt{0 + (12 - y)^2} \] 4. To find the values of \( y \), we need to solve: \[ 5 = |12 - y| \] This will result in two cases: 1. \( 5 = 12 - y \) 2. \( 5 = y - 12 \) 5. Solving these two cases will yield the possible values of \( y \). Note: While this guide explains the setup and initial process, complete solving to find all \( y \) is left as an exercise for the student. #### Additional Example: ### Evaluation of Quadratic Expressions 1. **Expression Given:** \[ 3(2)^2 - 4(2) \] Simplify Step-By-Step: \[ 3(
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