y''' — 4y'' + 13y' + 50y 0 y(0) = 4, y'(0) = 10, y’’(0) = 42 y(t) =

Q: tx' 3 - - (³ 4) X X = C1 (1) +02 10 + ()

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Q: 12e* y' - 2y'+ y = 3

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Q: Find y' for y=3x-3-7x-¹. y'=0

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Q: 4/3 5² = 2² -3 (2²) *² y' x

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Q: y = (x² – 1)lnx

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Q: Find y'' in y = x2 (x3 - 1)5

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Q: 2. y' = 4x(2y3 -y)

A: Given differential equation, y'=4x(2y-3-y)..........(i)⇒y'+4xy=8xy-3⇒y3y'+4xy4=8x...........(ii)

Q: Find y' and y". In(7x) y = x7 y' = y" %3D

A: The given function is: y=ln(7x)x7 Therefore, y'=1x7ddx(ln(7x))+ln(7x)ddx1x7    =1x717x·7+ln(7x)-7x8…

Q: Find y' and y". In(2x) y = 1- In(32) y' y"

A: The given function y = ln(2x)/(x^5):   Find the first derivative of the function y = ln(2x)/(x^5)…

Q: y''-7y +10=0, y(0)= 2 and y'(0) = 4

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Q: Find y'. In(5x) y = 4x y' =

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Q: 4y'''+12y''+13y'+10y=0

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Q: (3) The derivative of y = In √√x is (A) y' = √³ 2 (B) y' == / 1 (C) y' = 2√/x (D) y' = = 1/2 2x (E)…

A: As we know that, The Power law: ddxxn=nxn-1 The Chain rule: fgx'=f'gx·g'x And use the common…

Q: y''- y' - 6y = 6(2 - e x);  y(0) = 5;  y '(0) = -3

A: Explanation of the solution is given below...

Q: Find h' (2) if h(x) = 1n(x + √(x2 - 1)) h'(2) =

A: Given hx=lnx+x2-1

Q: find y as a function of x if: y'''-13y''+42y'=60e^x, y(0)=11, y'(0)=24, y''(0)=21

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Q: Find y'' in y = (1 - √x)-1

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Q: solve  w' + ((2w)/x) = x5,       w(0) = 1 what is w(1)

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Q: 3. y'+7=(-2x+ y)';y(0) = 0

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Q: xy' = 3y + 8x, y(2) = 8. y= ((8x^8/8)+3)x^3

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Q: 5. If y=5x²-3x + 10, give y'(-1)

A: We have to find the y'(-1).

Q: y''''' - 3y'''' + 3y''' - y" = 0

A: To solve y""'-3y""+3y"'-y"=0

Q: If h'(3) = 5 and h'(1) =-1, then h"(x)dz %3D (A) -6 (B) 4 (C) 5 (D) 6

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Q: Find y'' in y = (1 + 1/x)3

A: We first expand the given expression first.

Q: Solve X'

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Q: y''+4y=0  y(0)=5 , y'(0)=6 find the start and end values Y(s)=?

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Q: 5y'' + y = 0 y(x) =

A: Consider the differential equation  5y''+y=0

Q: 8) y'+y=17 sin(2t), y(0) =-1.

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Q: If Ax) = 2x+ 1and g(x) = x, Find g0)) %3D

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Q: y''''' + 8y''' + 16y' = 0

A: Given differential equation yV+8y'''+16y'=0 We have to find the general solution of the given…

Q: Find the solution of: y'' - y = 56e^(3t) With y(0) = 9 and y'(0) = 6. y =

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Q: Find h(x) if h'(x)= h(x): 5x (6-x²)² X and h(1) = -6.

A: NOTE: Refresh your page if you can't see any equations. . here we have take integration on both…

Q: Solve: y''' – y'' – 21y' + 45y = 0 y(0) = – 2, y'(0) = 15, y"(0) = - 84 | y(t) = %D

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Q: y(t)=(2t-1)(5t-5)^-1, find y'(t)

A: Using Quotient Rule of Derivatives

Q: y''=2x(y')2 , y(0)=4, y'(0)=−1

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Q: Find y'. In(5x) y = 7x

A: SOME RESULTS:     IF y= f(u) and u=g(x) then,  dydx=dydududx.      ddxuv=vdudx-udvdxv2,v is non…

Q: Find y'. y = [In(x5 + 3)]2 y' =

A: