y" – 2y' + y = -3 - x+x².

Q: Find the general solution for differential equation.

A: Use linear differential method to solve

Q: VI(v)²-(JxcosVx – sec Vx '= 1

A:

Q: sin 2 dx 4 Inx |(xy)sin*(! e ]dy + ху tan

A:

Q: y" +y = 1.

A:

Q: ?y" +xy' – 4y = 2x*

A:

Q: 5. y" + y - sec z tan z

A: Given that, The DE is following, y'' + y = secx tanx We have to find the general solution of this…

Q: -3-x+x. y (0) -2. y(0)

A:

Q: solve the differential equation e dy + 2y = 4ety ³² dx

A:

Q: d²y dx² 3 7 + 3y (dy) 2 + y ² (dy) ² 3 0 = 5x

A:

Q: y = C1e2" sen(x)+ C2e²" cos(x) +x² + C3x + C4.

A:

Q: (2xy4e + 2xy³ + y)dx + (x²y4ev - x²y²-3x)dy = 0

A:

Q: Sy't6=x+x

A: Given differential equation is y''+5y'+6=x3+x2.

Q: 7.Solve the linear differential equation for general solution

A:

Q: y'tanxsin2y = sin²x + cos²y

A: Assume t=cos2y then differentiate both side with respect to x to find dtdx .…

Q: dw + 3wdx + wdv - 4 dx = 0 (x+1) (x+1)²

A: Let us solve the linear differential equation in the next steps.

Q: 2. y' + p(x)y = q(x)

A: