y+ (2xy-e-2y) y' = 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
21

Transcribed Image Text:y' =0
blem
ven
em
le
is also exact.
In each of Problems 15 and 16, show that the given equation is not
factor. Then solve the equation.
exact but becomes exact when multiplied by the given integrating
15. x2y³ + x(1+ y²) y' = 0,
ation
M(x) + N(y) y' = 0
u(x, y) = 1/(xy³)
16.
(x + 2) sin y + (x cos y) y' = 0, p(x, y) = xe*
17.
Show that if (Nx - My)/M = Q, where Q is a function of
only, then the differential equation
M + Ny' = 0
has an integrating factor of the form
J
20.
21.
22.
μ(y) = exp
In each of Problems 18 through 21, find an integrating factor and solve
the given equation.
1
Q(y)dy.
18. (3x2y + 2xy + y³) + (x² + y²) y' = 0
(5)
19.
y'=e²x + y - 1
1+(x/y sin y) y' = 0
y+ (2xy-e-2y) y' = 0
Solve the differential equation
(3xy + y²) + (x² + xy) y' = 0
alt
using the integrating factor u(x, y) = (xy(2x + y))-¹. Verify that
the solution is the same as that obtained in Example 4 with a different
integrating factor.
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